Question

use a system of linear equations with two variables and two equations to solve. a number is 11 more than another number. twice the sum of the two numbers is 6. find the two numbers.

Answer 1

The value of required two numbers x and y are 7 and -4 respectively. These values are find out using Elimination method.

Let the required first number and second numbers be x and y respectively .

We have given that, one Number is more than other by 11

i.e., the difference of two numbers is equal to 11

x - y = 11. …..(1)

And twice the sum of the two numbers is 6 i.e.,

2(x + y) = 6 => 2x + 2y = 6 => x +y = 3 …….(2)

Now , equation (1) and (2) are linear equation with two variables x and y .

We shall solve above two equations and find out the value of two variables. Using Elimination method , In which value of one variable is find out by eliminate the second variable through their coefficient comparison.

Added the equation ( 1) and (2) we get, 2x = 14 => x = 7

Put the value of x in equation (1) we get,

7 – y = 11 => y = -4

Thus, we get the values of two variables x and y is 7 and -4 respectively.

To learn more about linear equation, refer:

brainly.com/question/21243732

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