Answer:
scalene and obtuse
Step-by-step explanation:
Answer:
T = 200 months
Step-by-step explanation:
Given the model to be
dp/dt = p(10-1-10-7p) where p(0) = 6000
dp/dt = p(-1-7p)
dp/dt = -p+7p²
But since P(0) = 6000
We plug this value into the equation
P = -6000+7(6000)²
P = -6000+252000000
P = 251994000. .limiting value
Differentiating dp/dt w.r.t p
dp/dt = -1+14p
dp'/dt = 14p-1
Plugging p(0) = 6000 into the above we have that
dp'/dt = 14(6000)-1
P' = 84000
Time population would be equal to 3/2 the limiting value
T = 3/2× 84000 = 126000
T = 25199400/126000
T = 199.99months
T = 200 months.
Answer:25760.61
Step-by-step explanation:just add them together
Answer attached as picture with explanation. Please check.
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