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cupoosta [38]
3 years ago
11

Ericka observed the total variation in the water level over 6.2 years to be −13.64 mm. She compared this to the average annual t

rend, which shows the water level rising 1.8 mm/year. Remember, she used 6.2 years as her time period. What is the difference between how much average water levels rose and how much the water level fell in the part of the river she observed?
__________millimeters
Mathematics
1 answer:
vekshin13 years ago
8 0

Answer:

In the area that she observed, the water level fell 13.64mm over 6.4 years, for an average annual rate of change of: -13.64 ÷ 6.2 = -2.2 mm/ year.

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Only answer if you’re sure :) need full equation. Will give Brainly!
BabaBlast [244]

Answer:

Step-by-step explanation:

Only one answer will do for this question and that is 1.

y/x = 5/5  =   1

y/x = 6/6  =  1

y/x = 1/1 = 1

The one you have to be careful with is when x = 0 y = 0. You can't solve this by using y/x  because 0/0 is undefined at this point.

7 0
2 years ago
Graph the function f(x)= -.05x+3
GREYUIT [131]

Answer:

Step-by-step explanation:

Slope:  

−

0.05

y-intercept:  

3

x

y

0

3

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7 0
3 years ago
What are the x- and y-coordinates of point C, which partitions the directed line segment from A to B into the ratio 5:8? Round t
s2008m [1.1K]

Answer: D) (1.2,-4.7)

Step-by-step explanation:

plug in the end corrdinates like it says in the equation that the problem gives you.

7 0
3 years ago
Read 2 more answers
Please help im so confused​
slava [35]

Answer:

\text{1. }50^{\circ}\\\text{2. }80^{\circ}

Step-by-step explanation:

1. The measure of an inscribed angle is always half the measure of the arc it forms. Since angle ACB forms arc AB with a measure of 100 degrees, the measure of angle ACB will be equal to \frac{100}{2}=\boxed{50^{\circ}}.

2. Relating to problem 1, both inscribed angles marked in the figure form the same arc. All inscribed angles forming the same arc will have the same measure. Therefore, the measure of angle GEF is equal to \boxed{80^{\circ}}.

3 0
2 years ago
Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher
Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.

A(t)=A_{0}(1/2)^t^/^h

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For A_{0 let's just assume that there are 100 original  atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

74=100(1/2)^t^/^5^7^3^0

Now, solve. First, divide by 100.

0.74=(0.5)^t^/^5^7^3^0

Take the log of everything

log(0.74)=\frac{t}{5730} log(0.5)

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get

5730\frac{log(0.74)}{log(0.5)} =t

Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0
3 years ago
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