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Leona [35]
1 year ago
11

The sum of an integer and 6 times the next consecutive odd integer is 61. Find the

Mathematics
1 answer:
vfiekz [6]1 year ago
4 0

If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

Consider the first odd integer as x

Then the next consecutive odd integer = x+2

The 6 times the second integer=  6(x+2)

= 6x+12

Sum of an integer and 6 times the next consecutive odd integer is 61

Then the equation will be

x + 6x+12 = 61

Add the like terms in the equation

(1+6)x + 12 = 61

7x +12 = 61

Move 12 to the right hand side of the equation

7x = 61-12

7x = 49

x = 49/7

x = 7

The second number is

x+2 = 7+2

= 9

Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

Learn more about equation here

brainly.com/question/28741857

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Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

Therfore we have that \overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}.

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Answer:

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Step-by-step explanation:

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