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1 year ago

11

The sum of an integer and 6 times the next consecutive odd integer is 61. Find the

1 answer:

vfiekz [6]1 year ago

4 0

If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

Consider the first odd integer as x

Then the next consecutive odd integer = x+2

The 6 times the second integer= 6(x+2)

= 6x+12

Sum of an integer and 6 times the next consecutive odd integer is 61

Then the equation will be

x + 6x+12 = 61

Add the like terms in the equation

(1+6)x + 12 = 61

7x +12 = 61

Move 12 to the right hand side of the equation

7x = 61-12

7x = 49

x = 49/7

x = 7

The second number is

x+2 = 7+2

= 9

Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

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The system crosses at the point (3, 4). How many solutions will the system have?

vagabundo [1.1K]

For this case suppose that we have a linear system of equations of the form:
ax + by = c
dx + ey = f
The solution of the system is an ordered pair of the form:
(x, y)
That is, both lines intersect at a point.
The point of intersection in this case is:
(3, 4)
Therefore, the system has one solution.
Answer
the system will have:
one solution

6 0

3 years ago

11. What is the location of the vertex of the parabola defined by f(x) = −3x2 − 18x − 35 and in what direction does the parabola

lbvjy [14]

11. The given parabola has equation: $f(x)=-3x^2-18x-35$

We complete the square to have the function in the vertex form: $f(x)=-3(x^2+6x)-35$

$f(x)=-3(x^2+6x+9)+3*9-35$

$f(x)=-3(x^2+6x+9)+27-35$

$f(x)=-3(x+3)^2-8$

The vertex is (-3,-8), the graph opens down because a=-3<0

Ans: B. Vertex: (−3, −8), opens downward

12. We know the graph of $y=x^2$ is a parabola that opens up and has its minimum point at the origin.

The range of this function is $y\ge 0$

A straight line that has its y-intercept below the x-axis (y=3x-6) will not intersect $y=x^2$ and hence will form a system with no solution.

Ans: D. y equals x squared, y equals 3x minus 6

14. We want to find the zeros of $x^2+21x=5x-63$

$x^2+21x-5x+63=0$

$x^2+16x+63=0$

The factored form is $(x+7)(x+9)=0$

$x=-7\:or\: x=-9$

Ans: C. x = −7, −9

15. The given quadratic expression is $6x^2-17x+10$

We split the middle term to obtain:

$6x^2-12x-5x+10=0$

We factor by grouping to get:

$6x(x-2)-5(x-2)=0$

$(x-2)(6x-5)=0$

Ans: D. 6x − 5

8 0

3 years ago

Read 2 more answers

{ y = - 4x-23-4x-3y=13

sleet_krkn [62]

For this case we have the following system of equations:

$y = -4x-23\\-4x-3y = 13$

We solve by the substitution method:

We substitute the first equation in the second equation:

$-4x-3 (-4x-23) = 13$

We apply distributive property considering that $- * - = +:$

$-4x + 12x + 69 = 13\\8x + 69 = 13$

We subtract 69 from both sides of the equation:

$8x = 13-69\\8x = -56$

We divide by 8 on both sides of the equation:

$x = \frac {-56} {8}\\x = -7$

We look for the value of the variable y:

$y = -4 (-7) -23\\y = 28-23\\y = 5$

Thus, the solution of the system is $(x, y): (-7,5)$

Answer:

$(x, y): (-7,5)$

7 0

3 years ago

24 ten thousands + 11 thousands on a chart

enot [183]

0.0035 is the answer brainliest plz

8 0

3 years ago

In 4th grade :) help plss

Soloha48 [4]

Answer:

1. 570

2. 5,700

3. 57,000

Step-by-step explanation:

Hope it helped

4 0

2 years ago

Read 2 more answers