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MakcuM [25]
2 years ago
12

The reason that most seti programs choose to listen at microwave radio frequencies is that.

Physics
1 answer:
Ugo [173]2 years ago
7 0

Microwaves are most energy efficient way to send information.

<h3>What are SETI programs?</h3>

Electromagnetic waves are a general term for familiar light and radio waves, but they also include gamma rays, X-rays, ultraviolet rays, and infrared rays. All of these forms of electromagnetic radiation or waves travel at the speed of light, the highest possible speed. The only difference between these types of electromagnetic waves is their length, or wave, or "wavelength." Another way to characterize waves is the number of waves received per second, since they all travel at the speed of light. This is the wave frequency. A specific range of radio frequencies from 1 GHz to 10 GHz, "microwaves", is particularly well suited for interstellar communications. At lower frequencies, our galaxy emits enormous amounts of radio waves, creating a large amount of background noise. At higher frequencies, the Earth's atmosphere, and possibly other Earth-like planets, absorb and emit a wide range of radio frequencies. The result is a quiet "microwave window" that enables efficient wireless communication.

To know more about SETI programs visit:

brainly.com/question/29432753

#SPJ4

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A sled with a mass of 20 kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that exerts a fricti
Ugo [173]

Use Newton's second law to determine the acceleration being applied to the sled. There are three forces at work on the sled (its weight, the force normal to the ground, and friction) but two of them cancel, leaving friction as the only effective force. This vector is pointed in the opposite direction of the sled's movement, so if we take the direction of its movement to be the positive axis, we would find the acceleration due to the friction to be

\vec F_G+\vec F_N+\vec F_F=m\vec a\iff-12\,\mathrm N=(20\,\mathrm{kg})a\implies a=-0.6\,\dfrac{\rm m}{\mathrm s^2}

Now we use the formula

{v_f}^2-{v_i}^2=2a(x_f-x_i)

to find the distance it travels. The sled comes to a rest, so v_f=0, and let's take the starting position x_i=0 to be the origin. Then the distance traveled x_f-x_i=x_f is

-\left(4.5\,\dfrac{\rm m}{\rm s}\right)^2=2\left(-0.6\,\dfrac{\rm m}{\mathrm s^2}\right)x_f\implies x_f\approx17\,\mathrm m

6 0
3 years ago
Calculate the electrical energy expended in a device across which the circuit voltage drops by 20.0 volts in moving a charge of
Inga [223]

Answer:

The answer is 80 Joules

Explanation:

Electrical energy = Q x V

Energy = 2 x 40

= 80

I just took the test and it was right :D

The correct answer is B.

I hope this helped! :D

6 0
4 years ago
AP PHYSICS SYSTEM OF EQUATIONS
Anon25 [30]

Walking at a speed of 2.1 m/s, in the first 2 s John would have walked

(2.1 m/s) (2 s) = 4.2 m

Take this point in time to be the starting point. Then John's distance from the starting line at time <em>t</em> after the first 2 s is

<em>J(t)</em> = 4.2 m + (2.1 m/s) <em>t</em>

while Ryan's position is

<em>R(t)</em> = 100 m - (1.8 m/s) <em>t</em>

where Ryan's velocity is negative because he is moving in the opposite direction.

(b) Solve for the time when they meet. This happens when <em>J(t)</em> = <em>R(t)</em> :

4.2 m + (2.1 m/s) <em>t</em> = 100 m - (1.8 m/s) <em>t</em>

(2.1 m/s) <em>t</em> + (1.8 m/s) <em>t</em> = 100 m - 4.2 m

(3.9 m/s) <em>t</em> = 95.8 m

<em>t</em> = (95.8 m) / (3.9 m/s) ≈ 24.6 s

(a) Evaluate either <em>J(t)</em> or <em>R(t)</em> at the time from part (b).

<em>J</em> (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m

8 0
3 years ago
It is very important to use _______ in your calculations
NeX [460]

Answer:

snoemw

Explanation:

4 0
3 years ago
Calculate the potential energy of a 6kg bowling ball suspended 3m above the surface of the earth
Valentin [98]

Answer:  176.4 Joules

Explanation: Potential energy of a body is defined as the energy possessed by virtue of position.

Potential energy =m\times g\times h

m = mass of the body = 6 kg

g = acceleration due to gravity = 9.8 ms^{-2}

h = height of body = 3 m

Potential energy =6 kg\times 9.8ms^{-2}\times 3m=176.4kgm^2s^{-2}

= 176.4Joules                 {1kgm^2s^{-2}=1Joule}


8 0
3 years ago
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