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ivolga24 [154]
3 years ago
15

Can someone help me please

Physics
2 answers:
xeze [42]3 years ago
6 0
Electrical energy is transformed into chemical energy
katen-ka-za [31]3 years ago
3 0
I think its thermal it may not be......

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Assertion : Human ear converts vibration with audible frequencies into electric signals. Reason : Audible sound lies in the rang
joja [24]
A I took I the test and r is the secondary
4 0
2 years ago
A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-
SVETLANKA909090 [29]

The resonant frequency of a circuit is the frequency \omega_0 at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

Where

L = Inductance

C = Capacitance

Our values are given as

C = 15*10^{-6}\mu F

L = 0.280*10^{-3}mH

Replacing we have,

f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})

f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})

f= 2455.81Hz

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.

7 0
4 years ago
Two wires carrying equal currents exert a force ???????? on each other. (a) The current in each wire is doubled, while the dista
sweet-ann [11.9K]

a) The magnetic field created by a current-carrying wire is proportional to the current:

B ∝ I, B = magnetic field strength, I = current

The magnetic force acting on a current-carrying wire immersed in a magnetic field is proportional to the current and the magnetic field strength:

F ∝ IB, F = magnetic force, I = current, B = magnetic field strength

Let's focus on wire 1.

Since wire 2's current is doubled, wire 2 produces a magnetic field twice as strong as before.

Wire 1's current is also doubled, therefore we now have a wire having <em>twice as strong a current</em> immersed in <em>twice as strong a magnetic field</em>. The magnetic force on wire 1 (and you can make a similar argument for wire 2) will be four times as strong as before.

b) The general formula for the magnetic force acting on a current-carrying wire immersed in a magnetic field is given by:

F = IL×B

F = magnetic force vector

I = current

L = vector having a magnitude equal to wire length and representing direction of current

B = magnetic field vector

Note we are taking a cross product of the IL and B vectors, not the product of two scalar quantities.

The very nature of the cross product means that if L and B are parallel to each other, F = 0N

7 0
3 years ago
How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?
Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

Q = ms\Delta T

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

Q = 3(385)(1085 - 83)

Q = 1157310 J

Q = 1157.3 kJ

now in order to melt the copper we know the heat required is

Q = mL

here we know that

L = 205 kJ/kg

now from above formula

Q = 3(205) kJ

Q = 615 kJ

now total heat required will be

Q = 1157.3 kJ + 615 kJ

Q = 1772.3 kJ

As we know that

1 Cal = 4.18 kJ

now we have

Q = \frac{1772.3}{4.18} = 430 KCal

6 0
3 years ago
What are the characteristics of S waves?
Reptile [31]
I think the answer is D
6 0
4 years ago
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