The reaction of radiodecay of carbon C-14 is
C-14 --> N-14 + e- + (ve)
where e- is an electron and (ve) is an electron-type antineutrino.
Basically, when the carbon nucleus (atomic number: 6, mass number: 14) decays, a neutron of the nucleus converts into a proton (therefore, the mass number remains the same, 14, but the atomic number increases by 1, therefore it becomes nitrogen) and releases an electron-antineutrino pair.
So, the correct answer is C), N-14.
Answer:
2.98 m/s^2
Explanation:
I have done this before and it was a question on my physics test
The frequency of the wave is 50 Hz
Explanation:
The frequency of the wave is defined as the number of cycles per second of the wave:

where
N is the number of cycles completed in a time t.
Frequency is measured in Hertz (Hz).
In this problems, the wave has
N = 100 pulses
in
t = 2.0 s
Therefore, its frequency is

Learn more about waves and frequency here:
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F=ma
Force is 50N. Acceleration is 25 m/s^2.
50N=m*25 m/s^2
Divide both sides by 25.
mass=2 kg