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sweet [91]
1 year ago
12

In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.

Mathematics
1 answer:
storchak [24]1 year ago
3 0

The length of q, to the nearest 10th of a centimeter is 7.6 cm.

Given in question,

In ΔOPQ,

o = 9.2 cm

p = 2.4 cm

∠Q = 37°

Cosine formula ⇒ cos θ = \frac{o^{2}+p^{2}-q^{2}  }{2op}

Putting the values in equation,

       cos 37 = \frac{(9.2)^{2}+(2.4)^{2}-q^{2}  }{2*9.2*2.4}

         0.799 = \frac{84.64 + 5.76-q^{2} }{44.16}

0.799*44.16 = 90.4 - q^{2}

         32.28 = 90.4 - q^{2}

                q^{2} = 90.4 - 32.28

                q^{2} = 58.12

                 q = \sqrt{58.12}

                 q = 7.63

q = 7.6 cm (to nearest 10th)

Hence, length of q is 7.6 cm.

Learn more about length on:

brainly.com/question/8552546

#SPJ1

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