When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.
If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.
Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so .
Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so .
Subtract from the first equation the second equation:.
Similarly you can prove that .
Pleas help will mark best answer!! <3
1 answer:
You might be interested in
It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: 
. FOIL out the left side to get 
. FOIL out the first of the 2 expressions on the right to get 
, and the second of the 2 to get 4x. Our equation now looks like this: 
. Combine like terms to get an equation that still has square roots in it that we have to deal with: 
and 
. We will square both sides to get rid of the square root sign. 
. This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. 
. Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2
