Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Yes, It is reasonable. I think this because you are dealing with 60 blocks, and out of every 5 blocks there are 3 red. 5 goes into 60 12 times. 3 multiplied by 12 is 36. 36 is more than 32. So, I think that it is reasonable. If this explanation didn't make sense, then feel free to ask for more. I hope this helped!
Answer:
See below for explanation of the examples.
Step-by-step explanation:
Left example
It is an exercise in addition, i.e. 48+122=170, the answer is written in the bottom box.
Right example
It is an exercise in subtraction, i.e. 8 1/2 - 3 1/2 = 5
The answer is written in the bottom box.
There is no indication though as to when to do the addition, and when to do the subtraction. Perhaps it would be shown in the rest of the page (not shown).
