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lana [24]
3 years ago
15

Simplify the expressions by combining like terms

Mathematics
2 answers:
Vesnalui [34]3 years ago
6 0

Hey!

---------------------------------------------------------

Question #1:

= 6n^2 - 2n - 3 + 5n^2 - 9n - 6

= 6n^2 + (-2n) + (-3) + 5n^2 + (-9n) + (-6)

= (6n^2 + 5n^2) + (-2n + -9n) + (-3 + -6)

= (11n^2) + (-11n) + (-9)

Answer: 11n² + (-11n) + (-9)

---------------------------------------------------------

Question #2:

= 8c^2 - c + 3 + 2c^2 - c + 2

= 8c^2 + (-c) + 3 + 2c^2 + (-c) + 2

= (8c^2 + 2c^2) + (-c + -c) + (3 + 2)

= (10c^2) + (-2c) + (5)

Answer: 10c² + (-2c) + 5

---------------------------------------------------------

Hope This Helped! Good Luck!

LiRa [457]3 years ago
3 0

Answer:

1. 11n^2-11n-9

2. 10c^2-2c+5

Step-by-step explanation:

1. 6n^2+5n^2 = 11n^2

-2n-9n = -11n

-3-6=-9

2. 8c^2+2c^2 = 10c^2

-c-c= -2c

3+2=5

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Show work <br> only do those <br> 32,34,36,38,40
Free_Kalibri [48]

Answer:  see below

<u>Step-by-step explanation:</u>

32)\quad \dfrac{3}{5}(x-12)>x-24

        3(x - 12) > 5(x - 24)

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      <u> -5x       </u>   <u>-5x         </u>

        -2x - 36 >      -120

        <u>      +36</u>      <u>    +36 </u>

        -2x        >       -84

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Graph:   ←------------o

                             42

34)   6[5y - (3y - 1)] ≥ 4(3y - 7)

        6[5y - 3y + 1] ≥ 4(3y - 7)

        6{2y + 1]        ≥ 4(3y - 7)

         12y + 6        ≥ 12y - 28

        <u>-12y            </u>    <u>-12y       </u>

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                        TRUE  so the solution is All Real Numbers

Graph:   ←-----------------------→

36)   BC  +  AC      > AB

         4    + 8 - AB > AB

                12 - AB  > AB

       <u>             +AB  </u>  <u>+AB </u>

                12          > 2AB

      <u>         ÷2        </u>    <u>÷2     </u>

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38)\quad \dfrac{1}{2}(y-16)\geq y+2\quad ;\text{claim}\ y\leq 20

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           then \frac{1}{2}(16 - 16) ≥ 16 + 2

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It looks a bit intimidating but it's actually very easy.

Instead of term a + b in the second equation we can say it's zero because the first equation describes a + b as being equal to 0.

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