Answer:
The one showing only the point (10, 3)
Or the linear plot with the point +10 highlighted.
Step-by-step explanation:
Answer: It would probably be 30
Step-by-step explanation:
The ratio is 10:0 , 20:10 , 30:20 , 40:30 , 50:40, 60:50 , etc…
so basically you just need to know the ratios!
Hope I could help :)
Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
3¼
Step-by-step explanation:

We take any of the two points shown in the question. I will take (-3, 1) and (1, 14).
x¹ = -3
y¹ = 1
x² = 1
y² = 14
Now, we sub these figures into the formula.

This leaves us with 14-1/1+3, which we can make into 13/4
13/4 = 3¼
<em>Disclaimer</em><em>:</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>actually</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>two</em><em>,</em><em> </em><em>but</em><em> </em><em>a</em><em> </em><em>way</em><em> </em><em>to</em><em> </em><em>distinguish</em><em> </em><em>one</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>other</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>label</em><em> </em><em>of</em><em> </em><em>sorts</em><em>.</em>
Answer:
The last one decreasing on the interval (-infinity, 0) where it becomes constant
Step-by-step explanation: