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d1i1m1o1n [39]
1 year ago
10

Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropria

te diagram, shade the appropriate region and then determine the value:P(9 <2 ≤ 14) = Note: Enter your answer up to 4 decimal places.

Mathematics
1 answer:
TiliK225 [7]1 year ago
8 0

GIVEN

The following values are given:

\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

z=\frac{x-\mu}{\sigma}

For x = 9:

\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}

For x = 14:

\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}

The probability can be calculated as follows:

P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671

The probability is 0.4671.

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2267.97 grams

Step-by-step explanation:

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Eric invited 200 of his friends to his graduation party. 75% of those invited said yes. 15% said no. The rest said maybe. 10% of
Ilia_Sergeevich [38]

Answer:

145

Step-by-step explanation:

75% of 200 = 150

75% + 15% = 90%

100% - 90% = 10%

10% of 200 = 20

10% of 150 = 15

150 + 15  - 20 = 145

145 friends attended the party.

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2 years ago
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3 0
3 years ago
PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi
Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

Hypotenuse^2=Base^2+Perpendicular^2

⇒ 5^2=3^2+4^2

Let a, b, c forms a Pythagorean triplet

a^2+b^2=c^2

Multiplied by 4 on both sides

⇒ 4a^2+4b^2=4c^2

⇒ {2a}^2+{2b}^2={2c}^2

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0
2 years ago
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