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d1i1m1o1n [39]
1 year ago
10

Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropria

te diagram, shade the appropriate region and then determine the value:P(9 <2 ≤ 14) = Note: Enter your answer up to 4 decimal places.

Mathematics
1 answer:
TiliK225 [7]1 year ago
8 0

GIVEN

The following values are given:

\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

z=\frac{x-\mu}{\sigma}

For x = 9:

\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}

For x = 14:

\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}

The probability can be calculated as follows:

P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671

The probability is 0.4671.

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finlep [7]

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Find the x and y intercepts 5y + 3x = 15
Tomtit [17]
First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

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We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

5y + 3x = 15
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So, the x-intercept is (5, 0) and the y-intercept is (0, 3)
8 0
3 years ago
What is14/3 simplflied​
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