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alisha [4.7K]
1 year ago
8

Barely learning this in school and not understanding it yet help

Mathematics
2 answers:
omeli [17]1 year ago
8 0

Answer:

The answer is in the picture I hope that is right

Step-by-step explanation:

Lera25 [3.4K]1 year ago
5 0

ANSWER

x=2184.67

EXPLANATION

We want to solve the given equation for x:

-3+8\log _9(3x+7)=29

First, add 3 to both sides of the equation:

\begin{gathered} -3+3+8\log _9(3x+7)=29+3 \\ 8\log _9(3x+7)=32 \end{gathered}

Divide both sides by 8:

\begin{gathered} \frac{8}{8}\log _9(3x+7)=\frac{32}{8} \\ \log _9(3x+7)=4 \end{gathered}

Convert from a logarithmic equation to an exponential equation:

\begin{gathered} \Rightarrow9^4=3x+7 \\ \Rightarrow3x+7=6561 \end{gathered}

Subtract 7 from both sides of the equation:

\begin{gathered} 3x+7-7=6561-7 \\ 3x=6554 \end{gathered}

Divide both sides by 3:

\begin{gathered} \frac{3x}{3}=\frac{6554}{3} \\ x=2184.67 \end{gathered}

That is the value of x.

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Step-by-step explanation:

Do PEMDAS

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There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
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Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

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x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

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Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

Now Subtracting equation 3 from equation 2 we get;

(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

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x+y=120\\38+y=120\\y=120-38\\y=82

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3 years ago
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