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1 year ago

Consider the surface with parametric equations .

1 answer:

5 0

There are two ways to express the tangent plane equation. Given that it is the sum of the two distinct tangent vectors, its parametric equation is r=r0+sru+trv.

<h3>What does the parametric surface in calculus mean?</h3>

A surface in Euclidean space is considered to be parametric if it can be described by a parametric equation with two variables. Parametric representation is another reasonably general technique for describing a surface in addition to implicit representation.

On the other hand, tangent planes to a surface are planes that are "parallel" to the surface at the point where they barely touch it. Remember that this provides us with a point on the The tangent plane equation can be written in two different ways. The following point emerges from the surface and tangent plane meeting at (x0,y0):

learn more about Tangent planes refer

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What Molecules can be found in the interstellar medium? A. Water, Carbon dioxide, and Hydrogen. B. Oxygen, Nitrogen and ammonia.

Masteriza [31]

The interstellar medium is the matter as well as the radiations that are found in the galaxies occupying the spaces between the star systems.
Interstellar medium is mainly composed of hydrogen that is followed by helium and trace amounts of nitrogen, oxygen and carbon (considered traces when compared to amount of hydrogen).

Therefor, the right choice is:
<span>A. Water, Carbon dioxide, and Hydrogen</span>

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3 years ago

What force would be required to accelerate a 1,100kg car to 0.5 m/s2

OlgaM077 [116]

Answer:

the force required to accelerate a 1,100kg car is 550N

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3 years ago

Light shined through a single slit will produce a diffraction pattern. Green light (565 nm) is shined on a slit with width 0.210

kondor19780726 [428]

Answer:(a)9.685 mm

(b)4.184 mm

Explanation:

Given

Wavelength of light $(\lambda )=565nm \approx 565\times 10^{-9}m$

Width of slit(b)=0.210

(a)Width of central maximum located 1.80m from slit

$=\frac{2\lambda L}{b}$

$=\frac{2\times 565\times 10^{-9}\times 1.8}{0.210\times 10^{-3}}$

=9.685 mm

(b)Width of the first order bright fringe

$Y_1=\frac{\lambda \times L}{b}$

$Y_1=\frac{565\times 10^{-9}\times 1.8}{0.210\times 10^{-3}}$

$Y_1=4.84mm$

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3 years ago

Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as h

Arturiano [62]

Answer:

A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.

So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.

So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle

As we know that arc length is given as

$L = R\theta$