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3 years ago

1.What type of sediment forms from minerals that crystallize from seawater?

2 answers:

7 0

The correct answers are as follows:
<span>1) hydrogenous sediment

2)sand and gravel

3) They rapidly break down at surface temperatures and pressures.</span>

umka21 [38]3 years ago

7 0

1.the correct answer is:

hydrogenous sediment

2.the correct answer is:

sand and gravel

3.the correct answer is:

they rapidly break down at the surface temperatures and pressures.

this is what i know

i did not copy the previous answer

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A motorcycle moves according to the velocity-time graph

Alexandra [31]

Answer:

a) 1 m/s²

b) -1 m/s²

c) 0 m/s² (constant speed, not accelerating)

Explanation:

delta speed = 10 - 0

delta time = 10 - 0

delta speed / delta time = 10/10

delta speed / delta time = 1

ds = 5 - 10

dt = 15 - 10

ds / dt = -5 / 5

ds / dt = -1

ds = 5 - 5

dt = 25 - 15

ds / dt = 0 / 10

ds / dt = 0

4 0

3 years ago

Read 2 more answers

3. A car going 22m/s accelerates to pass a truck. Five seconds late the car is going 35m/s. Calculate the acceleration of the ca

DedPeter [7]

Answer:

Explanation:

6 0

3 years ago

Question 1 Gary is on the space shuttle. It takes off and lifts him to a height of 300 km above Earth's surface. a. How has Gary

balandron [24]

A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.

b) The weight of an object is given by
$W=mg$
where
m is the mass
$g= \frac{GM}{r^2}$ is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.

At the Earth's surface, $g=9.81 m/s^2$ , so Gary's weight is
$W=mg=9.81 m$ (1)
where m is Gary's mass.

Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is
$R=6370 km$
So the distance of Gary from the Earth's center is
$r=R+h=6370 km+300 km =6670 km = 6.67 \cdot 10^6 m$

The Earth's mass is $M=5.97 \cdot 10^{24} kg$ , so the gravitational acceleration is
$g'=G \frac{M}{r^2}= (6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} )\frac{5.97 \cdot 10^{24} kg}{(6.67 \cdot 10^6 m)^2}=8.95 m/s^2$

Therefore, Gary's weight at 300 km above Earth's surface is
$W' = mg' = 8.95 m$ (2)

If we compare (1) and (2), we find that Gary's weight has changed by
$\frac{W'}{W}= \frac{8.95 m}{9.81 m}=0.91$
So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

6 0

3 years ago

Help with these please someone

Mice21 [21]

Answer:

Five: B

Ten: A

Explanation:

Five

An alpha decay looks like this.

$A^x_y====> B^{x-4}_{y - 2}+alpha^4_2$

So whatever is produced must have a mass of 4 less than 234 and a number on the periodic table of 2 less than 92. In other words, B has a mass of 230 and a number on the periodic table of 90.

The answer should be Thorium which is B.

Ten

There is actually not enough information to do 10. You get it by making an assumption and seeing if it works.

In general a beta decay can (the most common one ) look like this.

$A^x_y====> B^{x}_{y-1}+Beta^0_{-1}$

Is there anything that looks like that?

The weight stays the same (234) and the atomic number of the mother element (on the left) is 1 lower than the given chemical on the right.

$Th^{234}_{90}====> Pa^{234}_{91}+Beta^0_{-1}$

The answer is Thorium A

Beta decays are very tricky. Be very careful how you handle them. One of three items can be what is decayed. I have assumed it was an electron, but there are two other possibilities. I won't confuse you by adding them. Just be aware that they exist.

3 0

3 years ago

A copper wire of diameter 0.80 mm fails at an engineering stress = 248.2 MPa. Its ductility is measured as 75% reduction of area

Anvisha [2.4K]

Answer:

true stress = 992.8 MPA

true strain = 1.386

Explanation:

see the attached file

4 0

3 years ago