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Paladinen [302]
3 years ago
10

I NEED. HELP PLEASE, THANKS! :) Describe each Newton Law.

Physics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction

Explanation:

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1. Your new designer chair has an S-shaped tubular metal frame that behaves just like a spring. When your friend, who weighs 600
Anvisha [2.4K]

Explanation:

Given that,

Weight of the friend, W = 600 N

When the friend sits on the metal frame it bends downward 4 cm, we can say that the compression in the it is 4 cm or 0.04 m

To find,

Spring constant for this chair or k

Solve :

The weight of an object is equal to the force exerted by the gravitational force, F = 600 N

According to Hooke's law, the force exerted by the spring is given by :

F = kx

k is the spring constant

k=\dfrac{F}{x}

k=\dfrac{600\ N}{0.04\ m}

k = 15000 N/m

Therefore, the spring constant of the spring is 15000 N/m.

5 0
4 years ago
Need help ASAP
Citrus2011 [14]

Answer:

the phone call goes out, transmits through radio waves, then moves to the central hub. then the signals go to the nearest tower to the receiver if the call

8 0
3 years ago
Which competition is the “ most important soccer competition in the world “ ?
Ganezh [65]
It would be B. The World Cup

Hope this helps

Have a great day/night
8 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
Alguien me podria ayudar con esto pliz.. Ahora resuelva el siguiente ejercicio, tenga presente lo visto en clase y aprendido en
creativ13 [48]

Answer:

a.)1.)12m/s

2.)12m/s

3.)7m/s

4.)7m/s

5.)14m/s

6.)0m/s

b.)1.) 3m/s^2

2.)1.71m/s^2

3.).58m/s^2

4.).39m/s^2

5.).70m/s^2

6.)0

c.)1.)48m

2.)84m

3.)84m

4.)126m

5.)280m

6.)suma todos los metros mas 98m y obtendras la distancia en cual el carro se para

Explanation:

vinicial=0m/s

tiempo inicial=0s

Intervalo 1

v=12m/s

t=4s

aceleracion= vf-vi/t

=12-0/4

=12/4=3m/s^2

Intervalo 2

v=12m/s

t=7s

a=12/7

Intervalo 3

v=7m/s

t=12s

a=7/12

Intervalo 4

v=7m/s

t=18s

a=7/18

Intervalo 5

v=14m/s

t=20s

a=14/20

Intervalo 6

v=0m/s

t=27s

a=0/27

7 0
3 years ago
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