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Wewaii [24]
3 years ago
13

Mixed powders may be categorized as​

Physics
1 answer:
Nastasia [14]3 years ago
6 0

Answer:

<u><em>on  flow properties and free-flowing and cohesive. </em></u>

Explanation:

the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing

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An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
ololo11 [35]

Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}

P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}

P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

P =213.60 kg.m/s

\theta = tan^{-1}\dfrac{79.59}{198.22}

\theta = 21.87

the angle is \theta = 21.87 north of east

7 0
4 years ago
The bridges often have expansion joints to account for the changes in size due to temperature changes. Suppose a bridge is suppo
Helga [31]

Answer:

1.33 cm

Explanation:

L = 32 m, T 1 = 0 degree C , T2 = 32 degree C

Thermal expansion coefficient of steel, α = 13 x 106-6 per degree C

Let ΔL be the increase in length.

ΔL = L x α x ΔT

ΔL = 32 x 13 x 10^-6 (32 - 0)

ΔL = 0.0133 m = 1.33 cm

6 0
3 years ago
Someone please please please help me with this. I’ll give u whatever rating u want
tensa zangetsu [6.8K]

The vertical forces add up to zero.

The net force on the object is 60N to the right.

F = m • a

60N right = (10kg) • (a)

a = (60N right) / (10kg)

a = 6 m/s^2 to the right

Multi-engine Commercial would be nice.

5 0
3 years ago
3 examples of newtrons 2 law
frozen [14]

Explanation:

1) Kicking a ball.

2) Capture the ball by hand.

3) Push a car.

7 0
3 years ago
If a honeybee is flying 7.0 m/s, what is the kinetic energy (Joules) if its mass is 0.1 g?
svetlana [45]

Answer:

KINETIC ENERGY=K.E=0.00245 Joules ≈ 0.003 Joules

Explanation:

mass=m=0.1g=0.0001kg

velocity=v=7.0m/s

kinetic energy=K.E.=?

as we know that

kinetic energy=\frac{1}{2}mv^2\\ putting values\\kinetic energy=\frac{1}{2}(0.0001kg)(7.0m/s)^2\\ kinetic energy=\frac{1}{2} 0.0049joules\\kinetic energy= 0.00245Newton meter or joules

hope it will help ^_^

5 0
3 years ago
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