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3 years ago

Mixed powders may be categorized as

Physics

1 answer:

Nastasia [14]3 years ago

6 0

Answer:

on flow properties and free-flowing and cohesive.

Explanation:

the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing

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What object currently has the most gravitational potential energy? A, B, C, or D

eduard

Answer:

Explanation:

this because

gravitational potential energy = mass x height x gravitational field strength

so let's assume mass is 2 kg and gravitational field strength is 10 N /kg

so when height is very low, take it as 3 m

gravitational potential energy= 2 x 3 x 10 = 60 j

but when height is 6m

gravitational potential energy = 2 x 6 x 10 = 120 j

so when the height is the greatest, the gravitational potential energy is the highest

so A is the heighest so it has the highest gravitational potential energy.

hope this helps

please mark it brainliest :D

5 0

3 years ago

In a Hydrogen atom an electron rotates around a stationary proton in a circular orbit with an approximate radius of r =0.053nm.

leonid [27]

Answer:

(a): $F_e = 8.202\times 10^{-8}\ \rm N.$

(b): $F_g = 3.6125\times 10^{-47}\ \rm N.$

(c): $\dfrac{F_e}{F_g}=2.27\times 10^{39}.$

Explanation:

Given that an electron revolves around the hydrogen atom in a circular orbit of radius r = 0.053 nm = 0.053 $\times 10^{-9}$ m.

Part (a):

According to Coulomb's law, the magnitude of the electrostatic force of interaction between two charged particles of charges $q_1$ and $q_2$ respectively is given by

$F_e = \dfrac{k|q_1||q_2|}{r^2}$

where,

$k$ = Coulomb's constant = $9\times 10^9\ \rm Nm^2/C^2.$
$r$ = distance of separation between the charges.

For the given system,

The Hydrogen atom consists of a single proton, therefore, the charge on the Hydrogen atom, $q_1 = +1.6\times 10^{-19}\ C.$

The charge on the electron, $q_2 = -1.6\times 10^{-19}\ C.$

These two are separated by the distance, $r = 0.053\times 10^{-9}\ m.$

Thus, the magnitude of the electrostatic force of attraction between the electron and the proton is given by

$F_e = \dfrac{(9\times 10^9)\times |+1.6\times 10^{-19}|\times |-1.6\times 10^{-19}|}{(0.053\times 10^{-9})^2}=8.202\times 10^{-8}\ \rm N.$

Part (b):

The gravitational force of attraction between two objects of masses $m_1$ and $m_1$ respectively is given by

$F_g = \dfrac{Gm_1m_2}{r^2}.$

where,

$G$ = Universal Gravitational constant = $6.67\times 10^{-11}\ \rm Nm^2/kg^2.$
$r$ = distance of separation between the masses.

For the given system,

The mass of proton, $m_1 = 1.67\times 10^{-27}\ kg.$

The mass of the electron, $m_2 = 9.11\times 10^{-31}\ kg.$

Distance between the two, $r = 0.053\times 10^{-9}\ m.$

Thus, the magnitude of the gravitational force of attraction between the electron and the proton is given by

$F_g = \dfrac{(6.67\times 10^{-11})\times (1.67\times 10^{-27})\times (9.11\times 10^{-31})}{(0.053\times 10^{-9})^2}=3.6125\times 10^{-47}\ \rm N.$

The ratio $\dfrac{F_e}{F_g}$ :

$\dfrac{F_e}{F_g}=\dfrac{8.202\times 10^{-8}}{3.6125\times 10^{-47}}=2.27\times 10^{39}.$

6 0

3 years ago

1. What is the arrangement of the outer planets? 2. What effect does their placement have the planets?

Rasek [7]

the arrangement of the outer planets is
1. Mercury
2. Venus 
3. Earth 
4. Mars 
5. Jupiter 
6. Saturn 
7. Uranus 
8. Neptune
the inner most of the outer plannets is jupitor it is followed by saturn uranus and neptune

4 0

3 years ago

What is the mass of basswood wing with these dimensions: 26.9 cm x 5.5 cm x 0.15 cm?

Softa [21]

The answer is 22.1925 I hope you get right let me know I got my answer because I multiply it all together.

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3 years ago

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The density of iron is 7.87 g/cm3. If an iron cannonball has a volume of 105 cm3

Reptile [31]

the answer is 0.284 lb/in3

6 0