Answer:
Oxidation state] is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:
The oxidation state of a free element (uncombined element) is zero for a simple (monoatomic) ion, the oxidation state is equal to the net charge on the ion.
Hydrogen has an oxidation state of 1 and oxygen has an oxidation state of −2 when they are present in most compounds. (Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. H2O2 the algebraic sum of oxidation states of all atoms in a neutral molecule must be zero, while in ions the algebraic sum of the oxidation states of the constituent atoms must be equal to the charge on the ion.
The same is written in my textbook. But how am I supposed to find the ox. number of an atom, which is in compound like K2UO4?
Answer : The pressure of the gas is, 0.964 atm
Solution : Given,
Volume of gas = 9040 ml = 9.040 L (1 L = 1000 ml)
Moles of gas = 0.447 moles
Temperature of gas = 
Using ideal gas equation,
where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of gas
R = gas constant = 
Now put all the given values in this formula, we get the pressure of the gas.
By rearranging the terms, we get
Therefore, the pressure of the gas is, 0.964 atm
Answer:
Saturated
Explanation:
If the sugar sits undissolved at the bottom even after vigorous stirring, the lemonade has dissolved all the sugar it can hold. The lemonade is saturated.
If the lemonade were <em>unsaturated</em>, it could hold more sugar and that at the bottom would continue to dissolve.
The lemonade cannot be <em>supersaturated </em>because, if it were, the solid at the bottom would serve as nuclei on which the excess sugar in the solution could form more crystals.
