Standard form of a linear equation is Ax + By = C, where A, B, C are constants.
So,
y-8 = 3(x+1)
y-8 = 3x + 3
substract 3 from both sides,
y-8-3 = 3x+3-3
y-11 = 3x
substract y from both sides,
y-y-11 = 3x-y
-11 = 3x-y
So, the standard form is 3x-y = -11
Given Information:
Point 1 = (8, −3)
Point 2 = (4, −7)
Required Information:
Distance between points = d = ?
Answer:
Distance between points = d = √32 = 5.657
Step-by-step explanation:
We are given two points,
(x₁, y₁) = (8, −3)
(x₂, y₂) = (4, −7)
We are asked to find the distance between these two points.
The distance is given by

Substitute the given coordinates into above equation

Therefore, the distance between (8, −3) and (4, −7) is 5.657 units.
Answer:
Acute scalene triangle.
Step-by-step explanation:
Acute scalene triangle.
Sides: a = 4 b = 7 c = 8
Area: T = 13.998
Perimeter: p = 19
Semiperimeter: s = 9.5
Angle ∠ A = α = 29.995° = 29°59'41″ = 0.524 rad
Angle ∠ B = β = 61.028° = 61°1'42″ = 1.065 rad
Angle ∠ C = γ = 88.977° = 88°58'37″ = 1.553 rad
Height: ha = 6.999
Height: hb = 3.999
Height: hc = 3.499
Median: ma = 7.246
Median: mb = 5.268
Median: mc = 4.062
Inradius: r = 1.473
Circumradius: R = 4.001
Vertex coordinates: A[8; 0] B[0; 0] C[1.938; 3.499]
Centroid: CG[3.313; 1.166]
Coordinates of the circumscribed circle: U[4; 0.071]
Coordinates of the inscribed circle: I[2.5; 1.473]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 150.005° = 150°19″ = 0.524 rad
∠ B' = β' = 118.972° = 118°58'18″ = 1.065 rad
∠ C' = γ' = 91.023° = 91°1'23″ = 1.553 rad
Answer:
i dunno
Step-by-step explanation:
22.25
multiply them by each other and you will get your answer 22.25