Question

gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 0.962 g of methane is mixed with 1.2 g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.

Answer 1

The maximum mass of  produced will be,  2.16 grams

What is molar mass ?

In chemistry, the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance. This is the number of moles of that sample measured in moles. Molar mass is a mass property, not a molecular property of a substance. Molar mass is the average of many instances of a compound, which often differ in mass due to the presence of isotopes. Most commonly, molar mass is calculated from standard atomic masses, so it is a global average and a function of the relative isotopic abundances of constituent atoms on Earth. Molar mass is good for converting between the mass of a substance and the quantity of a bulk substance.

Mass of Methane = 0.962 g

Mass of  oxygen= 1.2 g

Molar mass of Methane= 16 g/mole

Molar mass of Oxygen = 32 g/mole

Molar mass of Water = 18 g/mole

First we have to calculate the moles of  and .

Now we have to calculate the limiting and excess reagent.

Moles of methane = 0.962 g/16 g/mole=0.060

Moles of oxygen = 1.2 g/32 g/mole=0.04

As, 1 moles of  CH₄ react with 2 mole of O₂

So, 0.06 moles of methane  react with 2 x 0.04 = 0.08 moles of oxygen

From this we conclude that, Oxygen is an excess reagent because the given moles are greater than the required moles and methane is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 1 mole of  react to give 2 moles of

So, 0.06 moles  of methane  react to give 0.06 x 2 = 0.12  moles of

Therefore, the maximum mass of  produced will be, 2.16 grams.

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