Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Answer:
Step-by-step explanation:
The answer is 1.3
Answer:
P =44 + 4xy
Step-by-step explanation:
To find the perimeter of a triangle, add up the three sides
P = 29+15+4xy
P =44 + 4xy
The answer would be 48 because the first answer is 60 minus the second answer which is 12 to get 48
Answer:
83 adult tickets and 217 student tickets.
Step-by-step explanation:
Let number of adult tickets sold = 
Given that total number of tickets = 300
So, number of student tickets = 300 -
Cost of adult ticket = $15
Cost of student ticket = $11
Total collection from adult tickets = $
Total collection from student tickets = 
Given that overall collection = $3630
So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.
Now , collection = $3632
