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3 years ago

5

Jada rewrites 5•3^x as 15x. Do you agree with Jada that these are equivalent expressions? Explain your reasoning. Help me please

e

1 answer:

Veseljchak [2.6K]3 years ago

7 0

Answer:yes

Step-by-step explanation:

5*3=15

5*3x=15x

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A scrap metal buyer pays $3.18 per square foot of steel.

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Answer:

2*3 = 6

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There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

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$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$

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2 years ago

Write an expression to represent "8 less than the product of 3 and j"

yarga [219]

(3*j)-8
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3 years ago

Elena randomly chooses a number from 1 to 10. What is the probability she chooses a number greater than 5?

zepelin [54]

ANSWER

$P(E)=\frac{1}{2}$

EXPLANATION

From the given information, Elena chooses a number from 1 to 10.

The sample space is

S={1,2,3,4,5,6,7,8,9,10}

n(S)=10

The numbers greater than 5 are:

E={6,7,8,9,10}

n(E)=5

The probability that, she chooses a number greater than 5 is:

$P(E) = \frac{n(E)}{n(S)}$

Substitute the values,

$P(E) = \frac{5}{10}$

$P(E) = \frac{1}{2}$

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3 years ago

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

$\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }$

$\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} }$

$\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3}$

$\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3}$

Hence, the correct choice is D

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2 years ago

Read 2 more answers