Question

22.6 grams of mercury ii nitrate, hg(no3)2 reacts with an excess of potassium, k. how many grams of mercury is formed? the other product is potassium nitrate, kno3.

Answer 1

Mass = 14.0 g of mercury is formed, 22.6 grams of mercury nitrate, hg(no3)2 reacts with an excess of potassium, k.

An inorganic substance with the formula Hg(NO3)2xH2O is mercury nitrate. Hot, concentrated nitric acid is used to process mercury to create it. By using X-ray crystallography, neither anhydrous nor monohydrate have been verified. The drug might have an impact on the kidneys, peripheral nervous system, and central nervous system. Ataxia, tremors. Given data: Mass of mercury nitrate = 22.17 g, Mass of mercury formed = ?

Solution:

Chemical equation:

Hg(NO₃)₂ + 2K    →    2KNO₃ + Hg

Number of moles of mercury nitrate:, Number of moles = mass/molar mass, Number of moles = 22.17 g / 324.6 g/mol, Number of moles = 0.07 mol, Now we will compare the moles of Hg(NO₃)₂ and mercury.

             Hg(NO₃)₂       :        Hg

                 1                :          1

              0.07             :       0.07

Mass of mercury: Mass = number of moles × molar mass, Mass = 0.07 mol × 200.6 g/mol

Mass = 14.0 g

Learn more about mercury nitrate here:

brainly.com/question/4588222

#SPJ4