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1 year ago

A. 25.0 ml of a solution of sodium hydroxide solution required 21.50 ml of 0.100 mol/l sulphuric acid for neutralisation.

Chemistry

1 answer:

nexus9112 [7]1 year ago

3 0

The concentration of the sodium hydroxide solution in mol/l is 0.176 M.

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Given

V =25 ml = 0.025 L

M = 0.1

C₁ = 0.1

V₁ = 21.50 = 0.022 L

C₂ = ?

V₂ = 25 ml = 0.025 L

C₁V₁ = C₂V₂

C₂ = C₁V₁ / V₂

= 0.1 * 0.022 * 2 / 0.025

= 0.176 M

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

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Answer :

The parent and daughter concentrations (in percentages) is, 60 % and 40 % respectively.

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First we have to calculate the parent and daughter concentrations (in percentages).

$\text{Parent concentrations}=\frac{1.8g}{3g}\times 100=60\%$

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$\text{Daughter concentrations}=\frac{(3-1.8)g}{3g}\times 100=40\%$

As we know that, the half-life of uranium-238 = $4.5\times 10^9$ years

Now we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{4.5\times 10^9\text{ years}}$

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Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.54\times 10^{-10}\text{ years}^{-1}$

t = time passed by the sample = ?

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a - x = amount left after decay process = 1.8 g

Now put all the given values in above equation, we get

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3 years ago

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Explanation :

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The chemical reaction will be:

$Na_2SO_4\rightarrow 2Na^++SO_4^{2-}$

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First we have to calculate the moles of $Na_2SO_4$

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Now we have to calculate the mass of $Na_2SO_4$

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