Answer:
enviornmental health perspectives
Explanation:
Answer:
0.861 L
Explanation:
We are given pressure, volume, and temperature, so let's apply the Combined Gas Law:
(P₁V₁)/T₁ = (P₂V₂)/T₂
Convert the temperatures to degrees Kelvin.
25.0°C -> 298 K, 100.0°C -> 373 K
Plug in the initial conditions on the left, then the final/new on the right, and solve for the unknown:
(165(2.5))/298 = (600(V₂))/373
V₂ = (165(2.5)(373))/(298(600))
V₂ = 0.861 L
Answer:
Sodium oxalate is a basic salt. In water it can be dissolved and dissociated.
The oxalic acid in water has two dissociations.
Explanation:
Na2C2O4 ---> 2Na+ + C2O4-2
Sodium oxalate is the conjugate base of a weak acid. In water this salt, dissociates completely giving rise to the sodium and oxalate ions. As Na+ comes from a strong base, in water it does not produce hydrolysis while oxalate does react in water, because it takes a proton from it and it generates a basic hydrolysis releasing OH-.
C2O4-2 + H2O ⇄ HC2O4- + OH-
In water the salt is basic. The pH of an aqueous solution of this salt is basic, since OH- is generated.
The HC2O4- has a second hydrolisis, it takes another proton from water to form oxalic acid.
HC2O4- + H2O ⇄ H2C2O4 + OH-
The oxalic acid acts as a weak acid, it can release 2 protons to water, to make oxalate (its conjugate base).
H2C2O4 + H2O ⇄ H3O+ + HC2O4-
HC2O4- + H2O ⇄ H3O+ C2O4-2
The HC2O4- acts as an ampholyte since it accepts and delivers protons simultaneously.
Answer:
Assume that the sack was initially close to the sea level. Its weight will increase even though its mass stays the same.
Explanation:
The weight of an object typically refers to the size of the planet's gravitational attraction (a force) on this object. That's not the same as the mass of the object. The weight of an object at a position depends on the size of the gravitational field there; on the other hand, the mass of the object is supposed to be same regardless of the location- as long as the object stays intact.
Let 
denote the strength of the gravitational field at a certain point. If the mass of an object is 
, its weight at that point will be 
.
Indeed, 
on many places of the earth. However, this value is accurate only near the sea level. The equation for universal gravitation is a more general way for finding the strength of the gravitational field at an arbitrary height. Let 
denote the constant of universal gravitation, and let 
denote the mass of the earth. At a distance 
from the center of the earth (where
.
The elevation of many places in Bhutan are significantly higher than that of many places in India. Therefore, a sack of potato in Bhutan will likely be further away from the center of the earth (larger ) compared to a sack of potato in India.
Note, that in the approximation, the value of is (approximately, because the earth isn't perfectly spherical) inversely proportional to the distance from the center of the planet. The gravitational field strength
On the other hand, the weight of an object of fixed mass is proportional to the gravitational field strength. Therefore, the same bag of potatoes will have a smaller weight at most places in Bhutan compared to most places in India.
