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valina [46]
3 years ago
13

Several bird species feed is a certain species of tree. Each bird species feeds in a different part of the tree. Which statement

is true of these birds species
Chemistry
2 answers:
Fofino [41]3 years ago
8 0

Answer:

They have adapted to different niches.

Explanation:

due to competition

AURORKA [14]3 years ago
7 0

Answer:

B.they have adapted to different niches due to competiton.

Explanation:

apexs

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MakcuM [25]
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4 0
3 years ago
Can anyone answer these ? 40 points !!
lesantik [10]

1st one is D

2nd one is A

4 0
3 years ago
The part of the flower responsible for producing pollen (sperm) is the _______.
IgorC [24]
Hello,

Here is your answer:

The proper answer to this question is option C "stigma".

Here is how:

The stigma is responsible for producing pollen in a plant.

Your answer is C.

If you need anymore help feel free to ask me!

Hope this helps!
7 0
3 years ago
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -&gt; 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J
Annette [7]

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\  \\ \text{       = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\  \\ \text{       = 541.3J/K.mol} \end{gathered}

Answer:

The correct answer is C.

5 0
1 year ago
An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.
Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 7°C - 84°C

ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

28.75211 kj

8 0
3 years ago
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