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ElenaW [278]
1 year ago
12

a(n) ? is an intentionally constructed, low-impedance electrically conductive path designed and intended to carry current during

ground-fault conditions from the point of grounding on a wiring system to the electrical supply source, and is intended to facilitate the operation of the overcurrent protective device or ground-fault detectors on a high-impedance system.
Engineering
1 answer:
tester [92]1 year ago
5 0

A effective ground-fault current path  is an intentionally constructed, low-impedance electrically conductive path designed and intended to carry current during ground-fault conditions from the point of grounding on a wiring system to the electrical supply source.

<h3>Is earth an effective ground fault current path?</h3>
  • Sticking the wire in the ground is not sufficient since the earth is not thought to be a reliable ground-fault current channel.
  • The electrical system of a building or other structure is based on grounding.
  • To give a fault current a secure path to travel, grounding is used.
  • When installing switches, light fixtures, appliances, and receptacles, a complete ground route must be kept.
  • The undesired current flow trips circuit breakers or blows fuses in a system that is correctly grounded.
  • Through the use of a grounding bank, effective grounding maintains voltages within predetermined limits during a line-to-ground fault (short-circuit condition).

To learn more about ground-fault current channel  refer,

brainly.com/question/28498355

#SPJ4

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Find the phasor form of:
mixer [17]

Answer:

I=24.598\angle 50.377

Explanation:

A tension or current expressed in cosine form and with a positive sign can be converted directly into a phasor. This is done by indicating the tension and the offset angle:

Acos(10\omega t +\phi)=A\angle \phi

So:

i(t)=10cos(10t+63)+15cos(10t-42)=10\angle 63 + 15\angle42=I

You can sum the phasors simply using a calculator, however, let's do it manually:

Let's find the rectangular form of each phasor using the next formulas:

A=\sqrt{a^2+b^2} \\\phi=arctan(\frac{b}{a})

For 10\angle 63

63=arctan(\frac{b}{a} )\\\\tan(63)=\frac{b}{a} \\\\b=a*tan(63)

10=\sqrt{a^2+(a*tan(63))^2} \\\\10^2=a^2+a^2*(tan(63))^2\\\\Solving\hspace{3}for\hspace{3}a\\\\a=\sqrt{\frac{100}{1+tan(63)^2} } =4.539904997\\\\and\hspace{3}b\\b=\sqrt{100-a^2} =8.910065242

So:

Z_1=a+bj=4.539904997+8.910065242j

For 15\angle 42

42=arctan(\frac{b_2}{a_2} )\\\\tan(42)=\frac{b_2}{a_2} \\\\b_2=a_2*tan(42)

15=\sqrt{a_2^2+(a_2*tan(42))^2} \\\\15^2=a_2^2+a_2^2*(tan(42))^2\\\\Solving\hspace{3}for\hspace{3}a_2\\\\a_2=\sqrt{\frac{225}{1+tan(42)^2} } =11.14717238\\\\and\hspace{3}b_2\\\\b_2=\sqrt{225-a^2} =10.0369591

So:

Z_2=a_2+b_2j=11.14717238+10.0369591j

Hence:

Z_T=Z_1+Z_2=(4.539904997+11.14717238)+(8.910065242+10.0369591)j\\Z_T=15.68707738+18.94702434j

Finally:

I=\sqrt{15.68707738^2+18.94702434^2} \angle arctan (\frac{18.94702434}{15.68707738} )=24.598\angle 50.377

7 0
3 years ago
If a construction company is considering a new type of material to use in their construction, which factors would they
Amanda [17]

I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.

4 0
3 years ago
What is the difference between a Datum and a Datum Feature? a) A Datum and Datum Feature are synonymous. b) A Datum is theoretic
aliina [53]

Difference between Datum and Datum feature is<em> 'Datum is theoretical and Datum feature is real'. </em>

Option: (b)

<u>Explanation:</u>

A Datum is a perfect plane, line, point or surface but only occurs theoretically.

However a Datum Feature is fully based on a tangible surface, axis or point on a part where that theoretical datum is located.

The reason behind in this is they are not equal to each other because the 'part surface' is never 100% perfect.

The important functional features of the Datum is controlled during measurements.

7 0
3 years ago
When an electrical signal travels through a conductive wire, it produces an electromagnetic (EM) field. Likewise, when an EM fie
PolarNik [594]

Answer:

A. True

Explanation:

When an electromagnetic field wave strikes a conductor, say a wire, it induces an alternating current that is proportional to the wave in the conductor. This is a reversal of generating electromagnetic wave from accelerating a charged particle. This phenomenon is used in radio antena for receiving radio wave signals and also use in medicine for body scanning.

5 0
3 years ago
CO is the abbreviation for
garri49 [273]

Answer:

CO is usually the abbreviation for company

Explanation:

8 0
4 years ago
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