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Leona [35]
3 years ago
7

If a construction company is considering a new type of material to use in their construction, which factors would they

Engineering
1 answer:
Amanda [17]3 years ago
4 0

I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.

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Which of the following would require the filing of an EIS? a. expansion of an airport in a national park b. allowing snowmobiles
alekssr [168]

Answer:

d. All of the above would require an EIS.

Explanation:

A document prepared with the aim of describing the impacts of suggested operations on the environment is an Environmental Impact Statement (EIS). There was a mistake. An Environmental Impact Statement (EIS) is therefore a report describing the environmental effects resulting from a current action. All of the activities above would have an effect on the environment and therefore must fill an EIS

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A 4140 steel shaft, heat-treated to a minimum yield strength of 100 ksi, has a diameter of 1 7/16 in. The shaft rotates at 600 r
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¿Que piensas respecto al hecho de que María y Efraín rara vez se comunican directamente?
AleksandrR [38]

Answer:

Crean un código usando la naturaleza.

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3 years ago
Grinding with the portable disc grinder should not be done in an area which​
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Nothing flammable of explosive type of material is around
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2 years ago
A walrus loses heat by conduction through its blubber at the rate of 220 W when immersed in −1.00°C water. Its internal core tem
Llana [10]

Answer:

The average thickness of the blubber is<u> 0.077 m</u>

Explanation:

Here, we want to calculate the average thickness of the Walrus blubber.

We employ a mathematical formula to calculate this;

The rate of heat transfer(H) through the Walrus blubber = dQ/dT = KA(T2-T1)/L

Where dQ is the change in amount of heat transferred

dT is the temperature gradient(change in temperature) i.e T2-T1

dQ/dT = 220 W

K is the conductivity of fatty tissue without blood = 0.20 (J/s · m · °C)

A is the surface area which is 2.23 m^2

T2 = 37.0 °C

T1 = -1.0 °C

L is ?

We can rewrite the equation in terms of L as follows;

L × dQ/dT = KA(T2-T1)

L = KA(T2-T1) ÷ dQ/dT

Imputing the values listed above;

L = (0.2 * 2.23)(37-(-1))/220

L = (0.2 * 2.23 * 38)/220 = 16.948/220 = 0.077 m

7 0
3 years ago
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