You said the answer in your question??
Answer:
Explanation:
class Pet:
def __init__(self):
self.name = ''
self.age = 0
def print_info(self):
print('Pet Information:')
print(' Name:', self.name)
print(' Age:', self.age)
class Dog(Pet):
def __init__(self):
Pet.__init__(self)
self.breed = ''
def main():
my_pet = Pet()
my_dog = Dog()
pet_name = input()
pet_age = int(input())
dog_name = input()
dog_age = int(input())
dog_breed = input()
my_pet.name = pet_name
my_pet.age = pet_age
my_pet.print_info()
my_dog.name = dog_name
my_dog.age = dog_age
my_dog.breed = dog_breed
my_dog.print_info()
print(' Breed:', my_dog.breed)
main()
Explanation:
Precision machining is a subtractive process used in cases where material needs to be removed from a raw product to create the finished product. Precision machining can be used to create a wide variety of products, items, and parts for any number of different objects and materials. These parts usually require tight tolerances variation from nominal dimensions and from part to part, which means that there is not much room for error in the production of the piece. Repeatability and well-controlled tolerances are hallmarks of precision machining. Components, parts and finished durable products that are designed to maintain extremely tight tolerance margins and a high degree of durability are essential and common drivers for utilization of precision machining. For example, parts that need to work together as part of a machine may need to always align within a certain margin of 0.01mm to 0.05mm. Precision engineering and machining help to ensure these parts can not only be made precisely but can be produced with this level of accuracy over and over again.
Answer: Coefficient= 0.35 per day
Explanation:
To find the bio degradation reaction rate coefficient, we have
k= 
Here, the C lagoon= 20 mg/L
Q in= Q out= 8640 m³/d
C in= 100 mg/L
C out= 20 mg/L
V= 10 ha* 1* 10
V= 10⁵ m³
So, k= 
k= 0.35 per day
