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3 years ago

List irreversibilities

Engineering

1 answer:

natali 33 [55]3 years ago

6 0

Answer:

Some of the irreversibilities are listed below:

Plastic deformation of solids
Transfer of heat over finite difference of temperature
When two fluids are mixed together the process is irreversible
Combustion of a gas
Current flowing through a finite resistor
Diffusion and free compression or expansion of gas
Relative motion of body with force of friction
Processes involving chemical reactions(spontaneous)

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Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.

Step2

Mean torque is calculated as follows:

$P=T\omega$

$P=T(\frac{2\pi N}{60})$

$100\times 1000=T(\frac{2\pi 160}{60})$

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

$T_{max}=(1+\frac{20}{100})T$

$T_{max}=1.2T$

$T_{max}=1.2\times 5968.31$

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

$\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}$

$70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}$

$d^{3}=5.211\times 10^{-4}$

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

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Answer:

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Answer:

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Explanation:

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The radial acceleration is given by;

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Where;

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R is the radius of the circular path

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Therefore, from the given options in the question, all the options are correct.

d. all of the above

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