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ss7ja [257]
1 year ago
14

During a game of roulette, a wheel is spun and a ball drops randomly into one of the wheel's numbered compartments. then the pro

cess is repeated with another random spin. are these two events dependent or independent?
Mathematics
1 answer:
scoray [572]1 year ago
6 0

The two events are independent of each other.

According to the question during a game of roulette, a wheel is spun and a ball drops randomly into one of the wheel's numbered compartments. The ball can drop in any one of the wheel's numbered compartments , there is no restriction on it.

Now,  the process is repeated with another random spin. when the process is repeated the ball can drop in any one of the wheel's numbered compartments , there is no restriction on it. As the first spin  does not affect the second spin, we can conclude that these two events are  completely independent of each other.

To know more about independent events refer to the link:

brainly.com/question/1374659

#SPJ4

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What fraction represents 0.1875 ft?
aliya0001 [1]

Answer:

There is not much that can be done to figure out how to write 0.1875 as a fraction, except to literally use what the decimal portion of your number, the .1875 , means. Since there are 5 digits in 1875 , the very last digit is the "100000th" decimal place. So we can just say that .1875 is the same as 1875/100000.

Step-by-step explanation:

3 0
3 years ago
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Please help? I’m super lost...
babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function.  Watch and see.

a.  sin2\theta =-\frac{\sqrt{3} }{2}

Take the inverse sin of both sides.  When you do that, you are left with just 2theta on the left.  That's why you do this.

sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )

This simplifies to

2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2.  Those are:

2\theta =\frac{5\pi }{6} and

2\theta=\frac{7\pi }{6}

Divide both sides by 2 in both of those equations to get that values of theta are:

\theta=\frac{5\pi }{12},\frac{7\pi }{12}

b.  tan(7a)=1

Take the inverse tangent of both sides:

tan^{-1}(tan(7a))=tan^{-1}(1)

Taking the inverse tangent of the tangent on the left leaves us with just 7a.  This simplifies to

7a=tan^{-1}(1)

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1.  They are:

7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}

Dibide each of those equations by 7 to find that the values of alpha are:

\alpha =\frac{5\pi}{28},\frac{\pi}{28}

c.  cos(3\beta)=\frac{1}{2}

Take the inverse cosine of each side.  The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems.  That simplifies to:

3\beta=cos^{-1}(\frac{1}{2})

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

3\beta =\frac{\pi}{6},3\beta  =\frac{5\pi}{6}

Divide each of those by 3 to find the values of beta are:

\beta =\frac{\pi }{18} ,\frac{5\pi}{18}

d.  sec3\alpha =-2

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

\frac{1}{cos(3\alpha) } =\frac{-2}{1}

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

cos(3\alpha)=-\frac{1}{2}

Now we will take the inverse cos of each side (same as above):

3\alpha =cos^{-1}(-\frac{1}{2} )

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

3\alpha =\frac{7\pi}{6},3\alpha  =\frac{11\pi}{6}

Dividing both of those equations by 3 gives us

\alpha =\frac{7\pi}{18},\frac{11\pi}{18}

And we're done!!!

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2 years ago
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Naily [24]
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3 years ago
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erastova [34]

Answer: 360 feet, or 3/44 of a mile

Step-by-step explanation: One yard is 3 feet, and 1760 yards are in a mile

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mr Goodwill [35]

Answer: (A) CDD

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then

C D D = (C C^-1) D = I D = D

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6 0
3 years ago
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