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anyanavicka [17]
1 year ago
11

Terry descends 110 feet in 10 minutes inside a cave. Which of the expressions shows Terry’s change in position from where he was

before descending.

Mathematics
2 answers:
erastovalidia [21]1 year ago
7 0

Answer: Answer D

Step-by-step explanation: Terry descended 110 feet in the air so where was he before he descended? -110 feet 110 feet away from the cave so reverse that and hes 110 feet away :) hope this helps and is right.

den301095 [7]1 year ago
3 0

Answer: D is the answer

Step-by-step explanation:  He was -110 feet 110 feet away from the cave so reverse that and he's 110 feet away

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Answer:

b

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Varvara68 [4.7K]

Answer:

<h2>Letter C</h2>

Step-by-step explanation:

If we look on the number line we see that there is a point on -3, another point on -1, 2, and 7.

These points tell us our answer, but the question states it doesn't have to be in any order.

As we look at answer A we see -3, 1, 2, and -7. That's incorrect since there is no positive 1 nor an -7.

As we look at answer B we see -3, 7, 1, and -2. That's incorrect since there is no positive 1, and not a -2.

As we look at answer D we see -2, 3, 1, and 7. That's incorrect since there is no positive 2, no positive 3, and no negative 1.

C has to be the correct answer since it's the only answer left and has the 4 numbers that are on the number line.

Therefore, the correct answer is C.

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3 years ago
Multiples of 6 are also multiples of 3
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3 years ago
Read 2 more answers
Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha
Pavel [41]

Answer:

(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14.

(Expand to obtain an equivalent expression for the sphere: x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0)

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}.

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}.

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between \left(x_1, \, y_1, \, z_1\right) and \left(x_2, \, y_2, \, z_2\right) would be:

\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right).

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}.

The equation for a sphere of radius r and center \left(x_0,\, y_0,\, z_0\right) would be:

\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2.

In this case, the equation would be:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2.

Simplify to obtain:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56.

Expand the squares and simplify to obtain:

x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0.

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Answer:

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Step-by-step explanation:

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