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AVprozaik [17]
1 year ago
12

Each page of a top-secret report on aliens requires 2 \text{ KB}2 KB2, start text, space, K, B, end text of space in digital for

mat.
What is the maximum number of pages the report can have so that it can be completely stored on a USB drive that holds 4 \cdot 10^6 \text{ KB}4⋅10
6
KB4, dot, 10, start superscript, 6, end superscript, start text, space, K, B, end text?
Write your answer in scientific notation, and round to one decimal place.
Mathematics
1 answer:
fredd [130]1 year ago
8 0

The maximum number of pages the report can have, using scientific notation, is of:

2 x 10^6.

<h3>What is scientific notation?</h3>

A number in scientific notation is written as follows:

a \times 10^b

With the base symbolized a \in [1, 10), meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1.

For this problem, the maximum number of pages that the report can have is given by the following division:

Maximum number of pages = Total capacity/Size of page.

These variables, from the text, are given as follows:

  • Total capacity: 4 x 10^6 KB.
  • Size of a page: 2 KB / page.

Hence the number of pages is obtained as follows:

Maximum number of pages = 4 x 10^6 KB / (2 KB/ page) = 2 x 10^6 pages.

When two numbers are divided in scientific notation, the bases are divided(4/2 = 2), while the exponents are subtracted (6 - 0 = 6).

More can be learned about scientific notation at brainly.com/question/16394306

#SPJ1

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Select all the statements that correctly describe the solutions to this system of equations?
Luba_88 [7]

x + y = 9

x = 9 - y

2x - y = 0

2(9 - y) - y = 0

18 - 2y - y = 0

-3y = -18

y = 6

x = 9 - y

x = 9 - 6

x = 3

5 0
3 years ago
For the equation 4(x - 2) = 4x + K which value of k will create an equation with no solutions?
lawyer [7]

Step-by-step explanation:

k=8 that is the equation with no solutions

5 0
3 years ago
For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9
Nezavi [6.7K]

Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

6 0
4 years ago
—5 + 3x + 2 = 12<br> Solve for x
klio [65]

Answer:

x=5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
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