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Fantom [35]
3 years ago
15

HELP ASAP!!!!Write a function g whose graph represents the indicated transformation of the graph of f.

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:that hard

Step-by-step explanation:

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How do you do 51 and 54?
NemiM [27]
51. I checked the comments but I still didn't understand it, sorry :/

54.

(43+45+47+49)=184

They are all odd and they are in consecutive order (one after another)
5 0
4 years ago
Geometry help please
Mariana [72]
The volume of a sphere is:

V=(4πr^3)/3, and you are told that r=5in so

V=(4π125)/3

V=500π/3 in^3

V≈523.60 in^3
4 0
3 years ago
Find the sum of 14 + 8 + 2+ ... + ( 274) + (-280).
Musya8 [376]

The sum of the given sequence is -6384.

<u>Step-by-step explanation:</u>

The given Arithmetic sequence is 14 + 8 + 2+ ... + ( 274) + (-280).

  • The first term of the sequence = 14
  • The last term of the sequence = -280
  • The common difference ⇒ 14 - 8 = 6

<u>To find the number of terms in the sequence :</u>

The formula used is n = (\frac{a_{n}-a_{1}} {d})+1

where,

  • n is the number of terms.
  • a_{n} is the late term which is -280.
  • a_{1} is the first term which is 14.
  • d is the common difference which is 6.

Therefore, n =(\frac{-280-14}{6}) +1

⇒ n =( \frac{-294}{6}) + 1

⇒ n = -49 + 1

⇒ n = -48

⇒ n = 48, since n cannot be negative.

∴ The number of terms, n = 48.

<u>To find the sum of the arithmetic progression :</u>

The formula used is S = \frac{n}{2}(a_{1} + a_{n} )

where,

  • S is the sum of the sequence.
  • a_{1} is the first term which is 14.
  • a_{n} is the late term which is -280.

Therefore, S = \frac{48}{2}(14+ (-280))

⇒ S = \frac{48}{2}(-266)

⇒ S = 48 \times -133

⇒ S = -6384

∴ The sum of the given sequence is -6384.

3 0
3 years ago
Whats the reciprocal of 9/14
velikii [3]
14/9 reciprocal is a reverse of the number so it should be opposite
i hope it helps
4 0
3 years ago
Read 2 more answers
Factor 8X squared + 10x + 2​
mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

4x² + 5x + 1 = (4x + 1)(x + 1) and

8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0
4 years ago
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