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Elina [12.6K]
1 year ago
15

john ran at a pace of 3.5 miles per hour for a distance of 10.5 miles. how many minutes did it take him to run 10.5 miles? use t

he distance formula: d
Mathematics
1 answer:
Rainbow [258]1 year ago
5 0

The minutes it takes him to run 10.5 miles is 180 minutes

<h3>How many minutes did it take him to run 10.5 miles?</h3>

The given parameters are

Speed = 3.5 miles per hour

Distance = 10.5 miles

The time is calculated as:

Time = Distance/Speed

So, we have

Time = 10.5 miles/3.5 miles per hour

Evaluate the quotient

Time = 3 hours

Convert to minutes

Time  = 180 minutes

Hence, the minutes it takes him to run 10.5 miles is 180 minutes

Read more about speed at:

brainly.com/question/6504879

#SPJ1

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You have 636.3 g of pennies and each penny weighs 3.03g. how many pennies do you have
nalin [4]
Total weight=number of pennies times weight of 1 penny
total weight/weight of 1 penny=number of pennies
636.3/3.03=210

210 pennies
8 0
3 years ago
-5.5 + 3.7 can u please help will mark branliest
Nadusha1986 [10]

Answer:

-1.8

Step-by-step explanation:

4 0
3 years ago
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Can someone please help
Ira Lisetskai [31]
E = 1/2(1.59 × 10^3)([2.7 × 10^1]^2)
plug it in to the o'l calculator and ¡bam!
4 0
3 years ago
Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
3 years ago
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($23 dollars per person)The cost of the hall for the dance is $4000 dollars How many people must attend the dance to cover the r
garik1379 [7]

Answer:

174

Step-by-step explanation:

Rental Fee ÷ Cost of Ticket = # of people needed

$4000÷$23=173.9....

Can't have .9 of a ticket, so round up to 174.

# of people needed is 174

8 0
3 years ago
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