john ran at a pace of 3.5 miles per hour for a distance of 10.5 miles. how many minutes did it take him to run 10.5 miles? use t
1 answer:
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Answer:
0.205177 mi
Step-by-step explanation:
Step 1: Find conversions
12 in = 1 ft
5280 ft = 1 mi
Step 2: Use Dimensional Analysis
0.205177 mi
Answer:
t=0 Sugar = 0 Kg
t=1min Sugar=0.27 Kg
Step-by-step explanation:
Data
Tank = 2640 L (pure water)
Sol=0.09kg Sugar per liter
Vin = Vout = 3L/min
Sugar in the beginning = ?
if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;