All categories

1 year ago

A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?

Physics

1 answer:

Alexxx [7]1 year ago

6 0

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

Mass (m) = 120 Kg
Distance (d) = 35 m
Time (t) = 150 s
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) = mg = 120 × 9.8 = 1176 N
Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

#SPJ1

You might be interested in

Find the transformation matrix that rotates a rectangular coordinate system through an angle of 60 about axes equal angels with

RSB [31]

Answer:

$M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]$

Explanation:

To find the matrix, let's decompose the vectors, the rotated angle is (-60C) for the prime system

x ’= x cos (-60)

y ’= y sin (-60)

we use

cos 60 = cos (-60)

sin 60 = - sin (-60)

we substitute

x ’= x cos 60

y ’= - y sin 60

the transformation system is

$\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}cos 60&0\\0&-sin60\end{array}\right] \ \left[\begin{array}{ccc}x\\y\end{array}\right]$ x '

the transformation matrix is

$M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]$

4 0

3 years ago

If you punch a wall with a force of 30 N, what force will you feel on you fist? F= N

Talja [164]

Answer:

Pain

Explanation:

6 0

3 years ago

Read 2 more answers

Satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an

Volgvan

Answer:

0.63

Explanation:

We are given that

Radius of earth, $R_E=6370 km$

Radius of orbit A, $R_A=7590+6370=13960 km$

Radius of orbit B, $R_B=6370+15800=22170 km$

We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.

Potential energy of orbit A= $U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}$

Potential energy of orbit B= $U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}$

$\frac{U_B}{U_A}=\frac{13960}{22170}=0.63$

Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63

8 0

4 years ago

This painting represents the milky way galaxy as it might appear from a distance. Identify the indicated features.

aksik [14]

The indicated features of how the painting represents the milky way galaxy include the following:

Spiral arm

Bulge

Disk

<h3>What is Milky way?</h3>

This is the galaxy which comprises of our solar system and has a milky appearance when it's viewed from the earth.

The painting represented it as a result of the spiral arm and other features which are listed above.

Read more about Milky way here brainly.com/question/13956361

5 0

2 years ago

(True or False Statement)

sertanlavr [38]

False is correct......

4 0

3 years ago