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Shkiper50 [21]
1 year ago
6

A moving walkway at the airport moves a 120Kg person 35m in 150s. How much power did this require?

Physics
1 answer:
Alexxx [7]1 year ago
6 0

The amount of power required to move the 120 Kg person to a distance of 35 m in 150 s is 274.4 W

<h3>How to determin the power</h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = force (F) × distance (d)

Therefore,

P = Fd / t

With the above formula, we can obtain the power as follow:

  • Mass (m) = 120 Kg
  • Distance (d) = 35 m
  • Time (t) = 150 s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Force (F) = mg = 120 × 9.8 = 1176 N
  • Power (P) = ?

P = Fd / t

P = (1176 × 35) / 150

P = 41160 / 150

P = 274.4 W

Thus, the power is 274.4 W

Learn more about power:

brainly.com/question/20353916

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Waves from a radio station have a wavelength of 369 m. They travel by two paths to a home receiver 20.0 km from the transmitter.
Olenka [21]

Answer:

92.25m

Explanation:

In order to solve the exercise, it is necessary to apply the concept of construtive interference due to a path difference.

The formula is given by,

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

where,

n is the index of refraction of the medium in which the wave is traveling

\lambda = wavelenght

\delta = is the path difference

m = integer (0,1,2,3...)

Since in this case we are dealing with an atmospheric environment, where air is predominant, we approximate n to 1.

And since we need the reflected wave,

\delta = 2x

Where x is the distance in one direction without return.

The distance must correspond to the minimum therefore m = 0, so

\delta = (m+\frac{1}{2})\frac{\lambda}{n}

\delta = ({0+\frac{1}{2})\frac{369}{1}

\delta = 184.5m

Then the minimum distance is:

x= \frac{delta}{2}

x = \frac{184.6}{2}

x = 92.25m

Therefore the minimum distance from the mountain to the receiver that produces destructive interference at the receiver is 92.25m

5 0
3 years ago
How do x ray measurements help us measure the amount of dark matter in galaxy clusters?
Kruka [31]

The temperature of the darc spaces can sometimes hike to extremely hot temperatures. Some amount of energy due to trapping matter inside is liberated and turned into light which can be seen in X-rays.

<h3>What are x-rays?</h3>

A piercing type of high-energy electromagnetic radiation is called X-radiation. The majority of X-rays have a wavelength between 10 picometers and 10 nanometers, which equates to frequencies between 30 petahertz and 30 exahertz.

X-ray scans show that a galaxy cluster's intergalactic region is extremely hot. This is due to the fact that the intergalactic medium, also known as the intergalactic media, is primarily composed of heated, ionized hydrogen with traces of heavier elements like silicon, carbon, and oxygen.

Instruments to detect X-rays must be transported to high altitudes by balloons, sounding rockets, and satellites since X-radiation is absorbed by the Earth's atmosphere.

To learn more about X-rays, here

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8 0
2 years ago
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
attashe74 [19]

Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The  tensile  strength of the nylon string is  600*10^{6} \  N/m^2

Answer:

A

   T = 471.3 \  N

B

 To prevent breakage the thickness of the string is increased

  String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

     The  diameter is  d =  1.00 \ mm  =  0.001 \  m  

       The  tensile strength of the nylon string is \sigma =  600 *10^{6} \  N/m^2

  Generally the radius is mathematically evaluated as

     r=  \frac{d}{2}

=>    r =  \frac{0.001}{2}

=>     r =  0.0005 \  m

The cross sectional area is mathematically represented as

     A = \pi  r^2

=>   A =  3.142  *  (0.005)^2

=>    A =  7.855*10^{-7}\  m^2

Generally the tensile strength of nylon is mathematically represented as

      \sigma  = \frac{T}{ A }

Where T is the tension on the maximum tension on the string

 So  

           T =  \sigma  *  A

=>          T =  600*10^{6} *  7.855*10^{-7}

=>         T = 471.3 \  N

Form the equation above  we  see that

        T  \  \alpha \  A

So if the tension is  increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional  area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

8 0
4 years ago
While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac
brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

v = \frac{d}{t}

Where

d = Distance

t = time

For which clearing the time we will have the expression

t = \frac{d}{v}

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

t = \frac{1300m}{3000m/s}

t = 0.433s

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

t = \frac{1300m}{343m/s}

t = 3.79s

The total difference between the two times would be

\Delta t = 3.79s-0.433s

\Delta t = 3.357s

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0
4 years ago
Consider a uniform sphere, which has a mass of 4.80 kg and a radius of 22.0 cm. A tangential force of 11.2 N is applied to the o
Tcecarenko [31]

Answer:

The moment of inertia of this sphere is 0.0929\ kg-m^2.                  

Explanation:

It is given that,

Mass of the sphere, m = 4.8 kg

Radius of the sphere, r = 22 cm = 0.22 m

Tangential force, F = 11.2 N

The moment of inertia of the uniform sphere is given by :

I=\dfrac{2}{5}mr^2

I=\dfrac{2}{5}\times 4.8\ kg\times (0.22\ m)^2

I=0.0929\ kg-m^2

So, the moment of inertia of this sphere is 0.0929\ kg-m^2. Hence, this is the required solution.              

8 0
3 years ago
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