Question

Consider a uniform sphere, which has a mass of 4.80 kg and a radius of 22.0 cm. A tangential force of 11.2 N is applied to the outer edge of this sphere:a. What is the moment of inertia of this sphere?

Answer 1

Answer:

The moment of inertia of this sphere is $0.0929\ kg-m^2$.                  

Explanation:

It is given that,

Mass of the sphere, m = 4.8 kg

Radius of the sphere, r = 22 cm = 0.22 m

Tangential force, F = 11.2 N

The moment of inertia of the uniform sphere is given by :

$I=\dfrac{2}{5}mr^2$

$I=\dfrac{2}{5}\times 4.8\ kg\times (0.22\ m)^2$

$I=0.0929\ kg-m^2$

So, the moment of inertia of this sphere is $0.0929\ kg-m^2$. Hence, this is the required solution.