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1 year ago

Find the volume of the irregular object a marble

Physics

1 answer:

Lostsunrise [7]1 year ago

7 0

By using Displacement method we can find volume of irregular object like marble.

<h3>What is displacement method?</h3>

In displacement method,

First , we measuring the volume of water displaced by an object which tell us the volume of the object.

Secondly We can use the physical balance to determine its mass.

Lastly , calculate the density by dividing the mass by the volume.

Procedure to find the Volume of irregular object i.e. marble

step 1 - Fill the graduated cylinder about half full and measure the initial volume of water.

step 2 - Drop the marble in the graduated cylinder.

step 3 -Now measure the final level of water.

Step 4 - Subtract both the values.

Here , comes the Volume of Irregular Object.

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When the starter motor on a car is engaged, there is a 310 A current in the wires between the battery and the motor. Suppose the

Blababa [14]

Answer:

Diameter will be 351.42 mm

Explanation:

We have given current flowing in the copper wire i = 310 A

Voltage drop across the wire V = 0.55 volt

We know that resistance is given by $R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega$

Length of the copper wire l = 1 m

Resisitivity of the copper wire $\rho =1.72\times 10^{-8}\Omega m$

We know that resistance $R=\frac{\rho l}{A}$

$0.00177=\frac{1.72\times 10^{-8}\times 1}{A}$

$A=969.4545\times 10^{-8}m^2$

As area $A=\pi r^2$

$3.14\times r^2=969.4545\times 10^{-8}$

$r=17.57\times 10^{-4}m$

So diameter $d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m$ = 351.42 mm

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3 years ago

What is the approximate size of Earth’s magnetic field? Where are Earth’s magnetic poles? Where is the magnet that causes Earth’

nataly862011 [7]

Earths poles are on opposite sides of the earth

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2 years ago

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The conventional system of signs that indicate relative durations of long and short sounds is called.

Rudiy27

Musical notation is the term used to describe the common system of signs used to denote the relative duration of long and short sounds.

<h3>What is a musical notation?</h3>

Music notation, often known as musical notation, is any technique used to graphically express audibly perceived music performed with instruments or sung by a human voice using written, printed, or other symbol-based representations. This includes notation for periods of silence like rests.

Throughout history, many civilizations have used different types of notation, and the knowledge of early musical notation is generally sparse. Different musical genres and cultural groups employ various methods of music notation, even during the same time period, such as the 2010s. For instance, while sheet music with staves and note-heads is the most popular method for professional classical musicians, the Nashville Number System is the main method used by professional country music session musicians.

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1 year ago

During the experiment if you could double the breakaway magnetic force with all other quantities left unchanged, what is the new

sergiy2304 [10]

There are some missing information in the question.
However, since you are talking about magnetic force, I think you refer to the Lorentz force. When a particle of charge q and velocity v is immersed in a magnetic field of intensity B, the force acting on the particle is:
$F=qvBsin\theta$
where $\theta$ is the angle between the magnetic field and the direction of the particle.
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2 years ago

A 500-N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area

weqwewe [10]

Answer:

W₂= 10000 N

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area (A2) of the piston:

Pressure is defined as the force (F) applied per unit area (A)

P=F/A (N/m²)

P1=P2

$\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }$

$F_{2} = \frac{F_{1}*A_{2} }{A_{1}}$ Equation (1)

Data

W₁ = weight sits on the small piston

F₁ = W₁= 500 N

A₁ = 2.0 cm²

A₂ = 40 cm²

Calculation of the weight (W₂) can the large piston support

We replace data in the equation (1)

$F_{2} = \frac{(500)*(40) }{2}$

F₂ = 10000 N

W₂= F₂= 10000 N

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3 years ago