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3 years ago

Workers do 8000 J of work on a 2000-N crate to push it up a ramp. If the ramp is 2 m high, what is the efficiency of the ramp?

Physics

2 answers:

IRISSAK [1]3 years ago

7 0

Answer:

50%

Explanation:

Efficiency = work out / work in

e = Fd / W

e = (2000 N) (2 m) / (8000 J)

e = 0.5

Anna11 [10]3 years ago

4 0

Answer:

50% efficiency

Explanation:

The efficiency is calculated with the following formula:

$e=\frac{workOut}{workIn}$

this can also be:

$e=\frac{WorkRequired}{WorkDone}$

which is more intuitive for the present problem.

the work required, using the definition of work as $W=F*d$ where $F$ is force in newtons, and $d$ is distance in meters.

$WorkRequired:F*d$

in this case $F=200N$ , and $d=2m$ , so the work required is:

$WorkRequired:(2000N)*(2m)$

$WorkRequired:4000J$

And the work done according to the problem is:

$WorkDone=8000J$

Thus, the efficiency is:

$e=\frac{WorkRequired}{WorkDone} =\frac{4000J}{8000J} =0.5$

And since $0.5=50$ %

⇒the answer is that the efficiency of the ramp is 50%

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GREYUIT [131]

Answer:

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Explanation:

The initial velocity of the glove, u =- 6 m/s

We need to find the maximum height of the glove. Let it is equal to h. Using equation of kinematics. At the maximum height v = 0

$v^2-u^2=2ah$ , h is the maximum height and a = -g

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3 years ago

Sandra takes a class field trip to a geology museum. She sees an interesting sample of igneous rock. She wonders if the material

Aleonysh [2.5K]

Answer:

Yes

Explanation:

It is possible for sedimentary rocks to be converted to igneous rocks. Under conditions of high temperature and pressure, sedimentary rocks can be broken down into igneous rock by melting this rock type.

When the rock is broken down, it forms melt which when cooled and solidifies will form igneous rocks.

Sedimentary rocks are formed from the breaking down of pre-existing rocks through the action of weathering, erosion and sediment transportation. Within a basin, the sediments are compacted and lithified.

When this is subjected to intense pressure and temperature, the rock hardens and might further break down to melt.

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3 years ago

You are holding a positive charge and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east. Wh

lara [203]

If I hold a positive charge in my hand and there are positive charges of equal magnitude 1 mm to your north and 1 mm to your east then the direction of the force on the charge I am holding is towards the north-east direction.

Reasoning:

It is given that there is a positive charge in my hand. There are two more positive charges with the same magnitude. One is 1 mm far towards the east, and the other one is 1 mm far towards the north. It is required to find the direction of the force acting on the charge in my hand.

Let the magnitude of the charge in my hand is Q, and the magnitude of the other charges is q.

Thus the electric force applied on the charge in my hand due to each other is,

$F=\frac{kQq}{r^2}$

Here k is the Coulomb constant, and r is the distance between the charges.

It is also known that the force on a positive charge due to another positive charge is acted outwards.

Thus, the force on the charge due to the charge on the east is,

$\vec{F_1}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{i}$

And the force on the charge due to the charge on the north is,

$\vec{F_2}=\frac{kQq}{( 10^{-3}\text{ m})^2}\hat{j}$

As the forces are equal in magnitude and one is perpendicular to the other, thus the net force will be acted at an angle of $45^\circ$ from the north or from the north direction.