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2 years ago

Graph the function with domain of all the real numbers: f(x) = 5 for x ≥ 3, and f(x) = -6 for x < 3

Mathematics

1 answer:

stiv31 [10]2 years ago

5 0

The graph of the given functions is (see in attachments).

Line Graph :

Graphs are visual displays of the data that have been gathered. Its goal is to visualize numerical data in a tangible way so that it may be quickly, simply, and clearly understood. A line graph is a special type of graph that is frequently employed in statistics. It shows how one quantity has changed in relation to another. For instance, we may use this graph to illustrate how the cost of various chocolate flavors fluctuates. Typically, a two-dimensional XY plane is used to plot this variation. A graph is said to be linear if it can represent the relationship between any two measurements by a straight line. Consequently, a line graph is often known as a linear graph.

To learn more about line graph visit: brainly.com/question/23680294

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Pat is required to sell candy bars to raise money for the 6th grade field trip. There is a 40%

eimsori [14]

Probabilities are used to determine the chances of events.

The given parameters:

$n = 5$ ---- the number of candy bars

$p = 40\%$ ---- the probability of selling a candy bar

(a) Name distributions

The distribution of X is represented as:

$X \sim(r,p)$

Where:

$r = 5$

$p= \frac{5\times 40\%}{10}$

$p= 0.2$

So, the name distribution of X is $X \sim(r= 5,p = 0.2)$

(b) The probability that the last candy is sold at the 11th house

This means that:

$n = 10$ --- the number of previous houses

$r = 4$ --- the previous number of candies

$p = 0.4$ --- the given probability of selling a candy

The probability is calculated using:

$P(x = n+1) = ^{n}C_r \times p^{r +1} \times (1 - p)^{n-r}$

This gives

$P(x = 10+1) = ^{10}C_4 \times 0.4^{4 +1} \times (1 - 0.4)^{10-4}$

$P(x = 11) = ^{10}C_4 \times 0.4^{5} \times (0.6)^6$

$P(x = 11) = 210 \times 0.4^5 \times 0.6^6$

$P(x = 11) = 0.1003290624$

Approximate

$P(x = 11) = 0.1003$

Hence, the probability that the last candy is sold at the 11th house is 0.1003

(b) The probability he sells the candies on or before the 8th house

The probability is calculated using:

$P(x \le 8) = P(5 \le x \le 8)$

This gives

$P(x \le 8) = ^{10}C_5 \times 0.4^{6} \times (0.6)^5 + ^{10}C_6 \times 0.4^{7} \times (0.6)^4 + ^{10}C_7 \times 0.4^{8} \times (0.6)^3 +^{10}C_8 \times 0.4^{9} \times (0.6)^2$

$P(x = 11) = 0.1737$ ---- approximated

Hence, the probability he sells the candies on or before the 8th house is 0.1737