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REY [17]
1 year ago
14

Need help with number 4. Verify algebratically if each function is even, odd, or neither

Mathematics
1 answer:
m_a_m_a [10]1 year ago
3 0

4. You have the following function:

f(x) = x^2 + 6

In order to determine if the prevous function is even, odd or neither, remind that you have odd and even function for the following cases:

f(-x) = f(x) even

f(-x) = -f(x) odd

Then, if you replace x by -x into f(x), you get:

f(-x) = (-x)^2 + 6

= x^2 + 6

= f(x)

Then, in this case f(-x) = f(x), hence, the function is even

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Answer:

The second option you listed: x + y = 4 gives the same line as H, and therefore renders infinite number of solutions (as many as every point on the line)

Step-by-step explanation:

We need to look for the equation that exactly matches the given one :

2 x + 2 y = 8

notice dividing both sides of this equation by "2" we get:

x + y = 4

SO this equation represents exactly the same line as 2 x + 2 y = 8 does, and therefore their graphs overlap completely

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b) the answer to the question is 2/3
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when a trend is drawn on the scatterplot there are 4 points above the trend line. about how many points should be below the tren
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4 0
4 years ago
Which statements are true? Select all that apply.
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cosθ = cotθ/cscθ is a true statement. The answer is option B

<h3>How to determine which of the trigonometric statements are true?</h3>

Trigonometry is a branch of mathematics dealing with the relationship between the ratios of the sides of a right-angled triangle with its angles

A. tan²θ = 1 - sec²θ

tan²θ = 1 - sec²θ  

tan²θ = 1 - 1/cos²θ               (Note: sec²θ  = 1/cos²θ)

tan²θ = (cos²θ- 1)/cos²θ

tan²θ =  -sin²θ/cos²θ            (Note: cos²θ- 1  =  -sin²θ)

tan²θ = -tan²θ

This statement is not true

B. cosθ = cotθ/cscθ

cosθ = cotθ/cscθ

cosθ = (1/tanθ) / (1/sinθ)

cosθ = (cosθ/sinθ).sinθ

cosθ = cosθ

This statement is true

C. 1/sec²θ   = sin²θ + 1  

1/sec²θ   = 1/(1/cos²θ)

1/sec²θ  = cos²θ

1/sec²θ  = 1 - sin²θ

This statement is not true

D. sec²θ - 1 = 1/cot²θ  

sec²θ - 1 = 1/cos²θ - 1

sec²θ - 1 = (1-cos²θ)/cos²θ

sec²θ - 1 = sin²θ/cos²θ

sec²θ - 1 = tan²θ

This statement is not true

E. sinθ cscθ  = tan θ  

sinθ cscθ  = tan θ

sinθ cscθ = sinθ (1/sinθ)

sinθ cscθ = 1  

This statement is not true

Therefore, the true statement is cosθ = cotθ/cscθ

Learn more about Trigonometry on:

brainly.com/question/29529966

#SPJ1

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