The length of ribbons found at a seamstress are listed.
2 answers:
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Answer:
f(j)=6j+5
f(1/3)=6*(1/3)+5
=2+5
=7
Answer:
176/1125 or 0.156
Step-by-step explanation:
There are 15 bulbs, of which 4 are 23-watt. The probability of selecting a 23-watt bulb = 4/15. If we call this probability x, then x = 4/15.
The probability of selecting a 13-watt or 18-watt bulb is the probability of not selecting a 23-watt bulb. If we call this y, y = (6+5)/15 = 11/15. It follows that x and y are mutually exclusive. Here, we have a binomial distribution.
The number of ways of selecting exactly two 23-watt bulbs out of three is
The probability of selecting them is