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hammer [34]
1 year ago
12

Two numbers have these properties.

Mathematics
1 answer:
taurus [48]1 year ago
8 0

With an HCF of 6 and an LCM of 60, the numbers 12 and 30 are greater than 6.

<h3>What are mathematical operations?</h3>
  • An operation in mathematics is a function that takes zero or more input values and produces a well-defined output value.
  • The operation's arity is determined by the number of operands.
  • Similar to the principle of superposition denotes a mathematical operation (e.g., differentiation, multiplication by a constant) in which the action on the sum of two functions is the sum of the action on each function.

Two numbers with HCF 6 can be:

6a, 6b where a, b are coprime numbers a, b > 1 as numbers greater than 6.

  • => 6 × 60 = 6a × 6b
  • => 10 = ab
  • ab = 10
  • 10 = 1 × 10  = 2 × 5
  • a , b > 1  

As a result, a and b can be 2 or 5.

The numbers are 6 × 2 and 6 × 5.

Therefore, with an HCF of 6 and an LCM of 60, the numbers 12 and 30 are greater than 6.

Know more about mathematical operations here:

brainly.com/question/18831322

#SPJ9

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weeeeeb [17]

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have

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… = (-2) / (-1)

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Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

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if you are asked to solve a system of equations in which there is no linear equation to start with, you can sometimes begin by i
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<u>Answer:</u>

The correct answer option is: True.

<u>Step-by-step explanation:</u>

Its true that if there is no linear equation to start with, you can isolate and substitute a variable that is squared in both the equation.

For example, for the given non linear equation, start by dividing both sides by coefficient of the variable.

Once you do that and isolate a variable, continue solving by substituting that variable into the other equation.

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