Plug in 7 for x and 24 for v
Lets x to be number of students.
1) If each students get 3 ml, then all students get 3x ml.
There was n ml.
(n-3x) ml leftover
n - 3x = 5
2) If each students get 4 ml.
then all students get 4x ml.
n+21 = 4x
3)
n - 3x = 5
- (n+21 = 4x) -------> -n -21=-4x
n - 3x = 5
<span>-n -21= - 4x
</span>-3x-21=5 - 4x
x=5+21
x=26
Answer : 26 students
Check:
x=26, n-3x = 5, n-3*26=5, n=83
n+21 = 4x
83+21=4*26
104 = 104 true
Answer:
y = 2x - 13
Step-by-step explanation:
Equation of a line is y = mx + c, m is the gradient and c is the intercept
The line passes through points 4 and -5, x is 4 and y is -5
-5 = 4m + c
When two lines are perpendicular, the products of their gradients are equal to -1, m1 * m2 = -1
x + 2y = 5
2y = -x + 5
y = (-1/2 * x) + 5
therefore m = -1/2
m1 * m2 = -1
m * -1/2 = -1
-m = -2 , therefore m = 2
-5 = 4 * 2 + c
c = -5 - 8, which is -13
Therefore the equation for the line is
y = 2x - 13
Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
