Answer:
I think it would be 34 because I divided 68.2 by 4 and got 17.05, so I multiplied that by 2, and it's closest to 34.
<em>So I think it's A.</em>
But y'all don't be mad if I'm wrong cuz I said I think.
X=2 because 5^3=125 and there you are
Paul surely charges 75 dollars, and then he adds 40 dollars per hours. This means that the expression for the money he asks is

where
is the amount of money and
is the number of hours.
Since
can be at most 8, this is the case that generates the highest money, so if we plug
we have

Given the geometric progression below

The nth term of a geometric progression is given below

From the geometric progression, we can deduce the following

To find the value of r, we will take ratios of two consecutive terms

To find the 9th term of the geometric, we will have that;

Hence, the 9th term of the geometric progression is 1953125