Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
D+b(3) just put them all together
Answer:
(D) 2√3
Step-by-step explanation:
From the above question ,we are asked to solve for:
6/√12 −√3
In other to simplify, we would expand the numerator of 6/√12
So we have;
= [6/(√4 ×√3)] - √3
= (6/ 2 ×√3) - √3
= (6/2 × √3) - √3
= (3 ×√3) - √3
= 3√3 - √3
= 2√3
Therefore, the value of 6/√12 −√3 is
option (D) 2√3
Answer:
1260cm^2
Step-by-step explanation:
15 times 12 = 180
180 times 7 = 1260