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liq [111]
3 years ago
13

Multiply. Express your answer in simplest form. 11 1/9 × 4 2/7

Mathematics
2 answers:
solmaris [256]3 years ago
5 0

Answer:

47 13/21

Step-by-step explanation:

Given

11 1/9 x 4 2/7

First change the fractions to improper fractions.

We have ,

100/9 x 30/7

Multiply through

3000/63

Divide the numerator and denominator by 3

1000/21

47 13/21

Kipish [7]3 years ago
4 0

Answer:

47 13/21

Step-by-step explanation:

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Please help me, thanks.
bixtya [17]
Your expression would be

(3 {}^{9}  - 4) - r
because of the order of operations this expression is valid to the world problem
3 0
3 years ago
Help! This question is extremely confusing! WILL GIVE A LOT OF POINT!
steposvetlana [31]

Answer:

<u>1035 feet</u>

Step-by-step explanation:

Taking the tan ratio of the angle of elevation :

  • tan 49° = h/900
  • 1.15 = h/900
  • h = 1.15 × 900
  • h = <u>1035 feet</u>
6 0
2 years ago
Read 2 more answers
The first 5 terms of a quadratic sequence are
Mashcka [7]

Step-by-step explanation:

an = 2n^2 - 3 · Anonymous. -1, 5, 15, 29, 47, ... an = 2 n^2 - 3.

8 0
2 years ago
Use logarithms to solve each equation 2x9/8=111
Illusion [34]
<span>We have this equation:
</span>
2x^{\frac{9}{8}} = 111

and we need to find the value of x.

First of all, we multiply the whole equation for 1/2, so our goal is to isolate x, therefore:

x^{\frac{9}{8}}=\frac{111}{2}
 
Next step we must do is to apply <span>logarithms:
</span>
logx^{\frac{9}{8}} = log(\frac{111}{2})

Next, we have to apply identities and then to solve the equation:

\frac{9}{8}logx = log(\frac{111}{2})
logx =  \frac{8}{9}log(\frac{111}{2})
logx = 1.5504
10^{logx} =  10^{1.5504}

Finally, we have the value of x which was our goal. This is the answer for the question above:

x= 35.5140

7 0
3 years ago
Solve the formula for the indicated variable <br> A=1/2bh solve for h
vfiekz [6]

Answer:

h=A*2b

Step-by-step explanation:

A=1/2bh

1/2bh=A

1/2bh÷1/2bh=A÷1/2bh (the 1/2b will cancel with the 1/2b on the left leaving h)

h=A*2b

7 0
3 years ago
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