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2 years ago

!!! PLEASE HELP RN !!! 3 (4 + 5) - 12 + 2

Mathematics

2 answers:

maksim [4K]2 years ago

6 0

Answer:

Step-by-step explanation:

Add (4 + 5) = 9 then multiply by 3 = 27 - 12 = 15 +2 = 17

iVinArrow [24]2 years ago

5 0

Answer:

$3(4 + 5) - 12 + 2 = 17$

Step-by-step explanation:

$3(4 + 5)$

break it down into PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

$3 \times 4 = 12$

$3 \times 5 = 15$

$15 + 12 = 27$

$3(4 + 5) = 27$

move onto your second part

$27 - 12 + 2$

$27 - 12 = 15$

$15 + 2 = 17$

your final part would be to put it all back together with your answer show an.

$3(4 + 5) - 12 + 2 = 17$

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anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

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So we can replace into our formula and we got:

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We have the following identities useful for this case:

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$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

And this identity is satisfied for all:

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