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meriva
3 years ago
5

!!! PLEASE HELP RN !!! 3 (4 + 5) - 12 + 2

Mathematics
2 answers:
maksim [4K]3 years ago
6 0

Answer:

17

Step-by-step explanation:

Add (4 + 5) = 9 then multiply by 3 = 27 - 12 = 15 +2 = 17

iVinArrow [24]3 years ago
5 0

Answer:

3(4 + 5) - 12 + 2 = 17

Step-by-step explanation:

3(4 + 5)

break it down into PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

3 \times 4 = 12

3 \times 5 = 15

15  + 12 = 27

3(4 + 5) = 27

move onto your second part

27 - 12 + 2

27 - 12 = 15

15 + 2 = 17

your final part would be to put it all back together with your answer show an.

3(4 + 5) - 12 + 2 = 17

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Solve for x<br> 3.24x + 8.37x -8.09=7.83<br> X= <br> Round your answer to the nearest hundredth
amm1812

3.24x + 8.37x -8.09=7.83

adding 3.24 x and 8.37x on the right side:

3.24x + 8.37x -8.09=7.83

11.61x -8.09=7.83

adding 8.09 to both sides:

11.61x =7.83+8.09

11.61x =7.83+8.09

11.61x =15.92

dividing both sides by 11.61

Answer : x=1.37

4 0
3 years ago
Suppose a geyser has a mean time between eruptions of 72 minutes. Let the interval of time between the eruptions be normally dis
nikitadnepr [17]

Answer:

(a) The probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is 0.3336.

(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 ​minutes is 0.0582.

(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is 0.0055.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) The population mean must be more than 72​, since the probability is so low.

Step-by-step explanation:

We are given that a geyser has a mean time between eruptions of 72 minutes.

Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.

(a) Let X = <u><em>the interval of time between the eruptions</em></u>

So, X ~ N(\mu=72, \sigma^{2} =23^{2})

The z-score probability distribution for the normal distribution is given by;

                            Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

Now, the probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is given by = P(X > 82 min)

       P(X > 82 min) = P( \frac{X-\mu}{\sigma} > \frac{82-72}{23} ) = P(Z > 0.43) = 1 - P(Z \leq 0.43)

                                                           = 1 - 0.6664 = <u>0.3336</u>

The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.

(b) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{13} } } ) = P(Z > 1.57) = 1 - P(Z \leq 1.57)

                                                           = 1 - 0.9418 = <u>0.0582</u>

The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.

(c) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 34

Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{34} } } ) = P(Z > 2.54) = 1 - P(Z \leq 2.54)

                                                           = 1 - 0.9945 = <u>0.0055</u>

The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 ​minutes, then we conclude that the population mean must be more than 72​, since the probability is so low.

6 0
3 years ago
Ben has a part time job at the fun station. Suppose he worked 13.5 hours last week and $81. How much does Ben earn per hour
scoundrel [369]

To get the answer, you will just use this operation: Division.
Let's divide it. 81 ÷ 13.5 = 6.

So, the answer is
Ben earns $6 per hour at the fun station.

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Answer:

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3(x - 5)^2 + 8

Now 2 units down :

3(x - 5)^2 + 8 - 2

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