On Thursday the high temperature was 0 °C. If it was three degrees colder on Friday, what was the temperature?
1 answer:
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6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3