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1 year ago

Which set of ordered pairs does not represent a function?

Mathematics

2 answers:

Leokris [45]1 year ago

7 0

<h3>Answer: Choice D</h3>

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Explanation:

Let's go through the four answer choices to see which are a function, and which aren't.

(A) This is a function since the x coordinates of the points are -6, 4, 1, 8; none of which repeat. Each x input leads to exactly one and only one y output.
(B) The same idea happens as it did with (A). The x coordinates are 3, -7, -2, 0 and none of those repeat. Therefore this is a function.
(C) Like with the others, none of the x coordinates repeat. We have another function.
(D) Unlike the others, x = -2 repeats itself twice. We have the point (-2,4) and (-2,5). This tells us the input x = -2 leads to simultaneous outputs of y = 4 and y = 5. This isn't allowed in a function (see part (A) above). Therefore, relation D is <u>not</u> a function.

If you wanted, you can use the vertical line test as a visual tool to check if we have a function or not. Graphs (A) through (C) will pass the vertical line test. Meanwhile graph D does not pass the vertical line test because of the points (-2,4) and (-2,5) mentioned earlier. You can use graphing tools like GeoGebra or Desmos.

Solnce55 [7]1 year ago

6 0

Answer: The last

Step-by-step explanation: 2 of the x values are the same

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A school goes through 10 gallons of milk in 3 days.

Akimi4 [234]

G = gallons d = days
10g = 3d
?g = 1d
1g = ?d
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for days per gallon, divide 10g = 3d by 10
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3 0

3 years ago

At a grocery store 4.5 pounds of meat cost $14.67. What is the cost of the meat per pound?

Elan Coil [88]

Answer:

$3.26

Step-by-step explanation:

If 4.5 pounds cost $14.67

You divide 14.67 by 4.5 which gives you 3.26

8 0

2 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

PLEASE HELP WILL GIVE BRAINLEIST

yan [13]

Step-by-step explanation:

You can prove it by pythegoras use unit and you will get

Ef=gh

And FG=EH

6 0

2 years ago

Change the decimal to a fraction and reduce .62

Len [333]

Answer:

31/50

Step-by-step explanation:

0.62 = 62/100 = 31/50

6 0

3 years ago