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Slav-nsk [51]
3 years ago
6

Mr. Shively’s TV cabinet is 30 inches tall and 40 inches wide. Best Buy is selling 50 inch, 55 inch, 60 inch, and 65 inch TVs. O

f those options, which one should he buy? Explain your answer using mathematics , please explain using Pythagorean theorem.

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer:

He should buy a 50 inch TV

Step-by-step explanation:

Using Pythagorean theorem the TV cabinet has a diagonal of :

\sqrt{30^{2} + 40^{2} } = 50

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A prize is divided in the ratio 5:1 if the larger share is £65 what is the total prize?
Paha777 [63]

Answer:

£78

Step-by-step explanation:

65 divided by 5= £13

13+65=£78

6 0
2 years ago
Read 2 more answers
C. What number is 40% of 1607?
Novay_Z [31]

Answer:

642.8

Step-by-step explanation:

1607 divided by 10 = 160.7 x 4 = 642.8

8 0
3 years ago
Wait so the sum of interior angles
Amiraneli [1.4K]
<h3>Answer:   1260</h3>

====================================================

Work Shown:

n = number of sides = 9

S = sum of the interior angles of any polygon with n sides

S = 180(n-2)

S = 180(9-2)

S = 180(7)

S = 1260

8 0
3 years ago
triangle MNO is an equilateral triangle with sides measuring 16 units What is the height of the triangle?
fiasKO [112]

see the attached figure to better understand the problem

we know that

The equilateral triangle has three equal sides

so

in the equilateral triangle ABC

AB=BC=AC=16 units

the height of the triangle is the segment BD

in the right triangle BCD

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

solve for BD

BD^{2}=BC^{2}-DC^{2}

substitute the values

BD^{2}=16^{2}-8^{2}

BD^{2}=192

BD=\sqrt{192}\ units

therefore

<u>the answer is</u>

the height of the triangle is \sqrt{192}\ units


7 0
3 years ago
Read 2 more answers
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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